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This question is confusing, I thought they were ranked in order so N had to be a value between 10.5 and 2 so I took 9 million as maximum value.
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This question is confusing, I thought they were ranked in order so N had to be a value between 10.5 and 2 so I took 9 million as maximum value.
­A certain country with a total population of 50 million is divided into six regions J, K, L, M, N and P, ranked from the most populated to the least populated, with some of the populations possibly equal. If 21 percent of the total population of the country is in region M and if the population of region P is 2 million, what is the greatest possible population of region N?

A. 5 million
B. 6 million
C. 7 million
D. 8 million
E. 9 million­

We are given that \(J \geq K \geq L \geq (M=10.5) \geq N \geq (P=2)\).

­To maximize N, we should minimize J, K, and L. The least values of them will be 10.5. Hence, we'd have

\((J=10.5) \geq (K=10.5) \geq (L=10.5) \geq (M=10.5) \geq N \geq (P=2)\).

Given that \(J + K + L + M + N + P =50\), then:

\(4*10.5 +N + 2 =50\)

\(N = 6\)

Answer: B.­
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Bunuel why can't we maximize "N"
M+P=12.4
N+J+K+L=37.6
maximum value of N = 37.6/4 = 9.4?
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Bunuel why can't we maximize "N"
M+P=12.4
N+J+K+L=37.6
maximum value of N = 37.6/4 = 9.4?
­Becasue in this case J, K, or L would become less than M = 10.5, while we are given that  \(J \geq K \geq L \geq (M=10.5) \geq N \geq (P=2)\).­
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­A certain country with a total population of 50 million is divided into six regions J, K, L, M, N and P, ranked from the most populated to the least populated, with some of the populations possibly equal. If 21 percent of the total population of the country is in region M and if the population of region P is 2 million, what is the greatest possible population of region N?

A. 5 million
B. 6 million
C. 7 million
D. 8 million
E. 9 million­


J, K, L, M,N, P

P=2 million, means 4%, and we know that M is 21%, so J+ K+ L+ N = 75%, N is highest when J, K,L are lowest, we know that M is 21%, so J=K=L=M =21% => N=12%. => population in N = 12% x 50 mil = 6mil
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