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­Let the cost = \(c\) and let profit = \(p\).

A price that would enable him to offer 10% discount and make a profit of 20% on cost: \(\frac{9}{10}(c+p)=\frac{12}{10}c\) [asking price will be c+p]

\(\frac{9}{10}p = \frac{3}{10}c\)

We are told that \(c = 30\), plugging that into the above: \(\frac{9}{10}p = \frac{3}{10}(30)\)

\(\frac{9}{10}p = 9\)

\(p = 10\)

Therefore \(c+p = 30+10 = 40\)

ANSWER E


 
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Asking Price = x

Offered 10% discount, means Selling price = 90%*x = 0.9x

Cost = $30

Profit = 20% of Cost = 0.2*30 = $6

Also, Profit = Selling price - Cost
Which gives 6 = 0.9x - 30

Simplifying gives x = 40

Answer is E
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