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Difficulty:
35%
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Question Stats:
72% (01:38) correct
28%
(02:02)
wrong
based on 50
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Asif, Rakib and Saad have x, y and z number of marbles respectively. If x = 6y = 3z,what fraction of his marbles should Asif give to Rakib and Saad so that all of them have equal numbers of marbles?
A. 1/5
B. 1/4
C. 1/3
D. 1/2
E. None of these
A. 1/5
B. 1/4
C. 1/3
D. 1/2
E. None of these
Let the variable be x, y and z
given x = 6y and x = 3z
we can write
y = x/6
z = x/3
Total number of marables
Total marable = x + y + z = x +x/6 + x/3 = 3x/2
To be distributed equally among asif, rakib and saad, each will get
(3x/2)/3 = x/2
Asif need to give away = x - x/2 = x/2
fraction of marble asif gave away = (x/2)/x = 1/2
so the answer is 1/2
Option D
given x = 6y and x = 3z
we can write
y = x/6
z = x/3
Total number of marables
Total marable = x + y + z = x +x/6 + x/3 = 3x/2
To be distributed equally among asif, rakib and saad, each will get
(3x/2)/3 = x/2
Asif need to give away = x - x/2 = x/2
fraction of marble asif gave away = (x/2)/x = 1/2
so the answer is 1/2
Option D
01 Jul 2024, 02:23
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since x = 6y = 3z
x/6 = y
x/3 = z
adding all these we get
x+x/6+x/3 = 3x/2
(3x/2)/3 = x/2
Asif has to give away half his marbles to make x = y = z
x/6 = y
x/3 = z
adding all these we get
x+x/6+x/3 = 3x/2
(3x/2)/3 = x/2
Asif has to give away half his marbles to make x = y = z
