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07 Jan 2025, 01:30
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
83% (01:10) correct
17%
(02:01)
wrong
based on 258
sessions
History
Date
Time
Result
Not Attempted Yet
\((2^3-1)(2^3+1)(2^6+1)(2^{12}+1)=\)
A. \((2^{24} -1)\)
B. \((2^{24} +1)\)
C. \((2^{48} -1)\)
D. \((2^{96} +1)\)
E. \(2^6(2^{12} -1)\)
A. \((2^{24} -1)\)
B. \((2^{24} +1)\)
C. \((2^{48} -1)\)
D. \((2^{96} +1)\)
E. \(2^6(2^{12} -1)\)
07 Jan 2025, 03:02
Kudos
Bookmarks
Solving the first 2 terms for a^2-b^2 will give the third term and again applying the same logic will yield option A
07 Jan 2025, 08:29
Kudos
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(2^3 - 1)(2^3 + 1)(2^6 + 1)(2^12 + 1)
[(2^3)^2 - (1)^2] (2^6 + 1)(2^12 + 1)
(2^6 -1) (2^6 + 1)(2^12 + 1)
(2^12 -1)(2^12 +1)
(2^24 -1)
Answer: A
[(2^3)^2 - (1)^2] (2^6 + 1)(2^12 + 1)
(2^6 -1) (2^6 + 1)(2^12 + 1)
(2^12 -1)(2^12 +1)
(2^24 -1)
Answer: A
