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29 May 2025, 00:30
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
88% (01:48) correct
13%
(02:12)
wrong
based on 104
sessions
History
Date
Time
Result
Not Attempted Yet
How many integers from 1 to 603, inclusive, are multiples of 2 or 3?
A. 300
B. 402
C. 406
D. 408
E. 410
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
A. 300
B. 402
C. 406
D. 408
E. 410
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
29 May 2025, 00:45
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Multiples of 2 = (602-2)/2+1 = 301
Multiples of 3 = (603-3)/3+1 = 201
Multiples of 6 = (600-6)/6+1 = 100
Total = 301+201-100 = 402
Multiples of 3 = (603-3)/3+1 = 201
Multiples of 6 = (600-6)/6+1 = 100
Total = 301+201-100 = 402
Bunuel
29 May 2025, 08:36
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Total number of multiples of 2 or 3 = (multiples of 2)+(multiples of 3)-(common multiples of 2&3)
2,4,6,8......,602
Multiples of 2= ((602-2)/2)+1= 301
2,6,9,12,......,603
Multiples of 3= ((603-3)/3)+1=201
6,12,18,24,......600
Multiples of 6= ((600-6)/6)+1=100
Total= 301+201-100=402
Answer: B
2,4,6,8......,602
Multiples of 2= ((602-2)/2)+1= 301
2,6,9,12,......,603
Multiples of 3= ((603-3)/3)+1=201
6,12,18,24,......600
Multiples of 6= ((600-6)/6)+1=100
Total= 301+201-100=402
Answer: B
