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26 Jan 2026, 12:50
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
66% (02:50) correct
34%
(03:08)
wrong
based on 96
sessions
History
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Time
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The distance between points P and Q is 108 miles. Two joggers start running from P and Q simultaneously toward each other. The jogger who starts from P runs at a constant speed of 6 miles per hour. Meanwhile, the other jogger runs with varying speeds: in the first hour, the speed is 4 miles per hour; in the second hour, it is 5 miles per hour; in the third hour, it is 6 miles per hour; and so on. When will they meet each other?
A. 48 miles away from P
B. 32 miles away from Q
C. After 18 hours from the start
D. After 5 hours from the start
E. Midway between P and Q
A. 48 miles away from P
B. 32 miles away from Q
C. After 18 hours from the start
D. After 5 hours from the start
E. Midway between P and Q
29 Jan 2026, 06:37
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Took me around 3 mins, need to figure out a faster way:
The distance travelled with their combined speed increases each hour like an AP: 6+4, 6+5, ..... = 10+11+12+...
So n/2[2a + (n-1)] = Sum of AP
n[20+n-1] = 216
n^2 + 19n - 216 = 0
n = 8
In 8 hrs, P has travelled 48 miles. So opiton A.
The distance travelled with their combined speed increases each hour like an AP: 6+4, 6+5, ..... = 10+11+12+...
So n/2[2a + (n-1)] = Sum of AP
n[20+n-1] = 216
n^2 + 19n - 216 = 0
n = 8
In 8 hrs, P has travelled 48 miles. So opiton A.
29 Jan 2026, 09:21
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I used the same method as yours but looking at the quadratic equation, I skipped solving it & checked the options and tried out by using the data in the option and marked A.
Prakhar2499
