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12 Mar 2026, 19:00
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68% (01:40) correct
32%
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The arithmetic mean of a list of 11 distinct positive integers is 13. What is the maximum possible value of the highest integer in the list?
A. 23
B. 75
C. 88
D. 98
E. Greater than 98
A. 23
B. 75
C. 88
D. 98
E. Greater than 98
12 Mar 2026, 22:11
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This can be done fast intuitively!
To create max value the highest integer, we need to minimize all other values.
How can we do that? By taking all number from 1 to 10 for the first 10 values!
And we know sum of first 10 positive integers is 55
Now we have total sum as 11*13 = 143
Therefore last value will be 88 here
Answer: Option C
To create max value the highest integer, we need to minimize all other values.
How can we do that? By taking all number from 1 to 10 for the first 10 values!
And we know sum of first 10 positive integers is 55
Now we have total sum as 11*13 = 143
Therefore last value will be 88 here
Answer: Option C
ExpertsGlobal5
13 Mar 2026, 05:42
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The list sums to 11×13=143.
To maximize the largest number, use the smallest 10 distinct positive integers: 1 through 10 (sum 55).
This leaves 143−55=88 for the largest, forming a valid list (e.g., 1-9, 10, 88).
The maximum possible value is 88.
ANS = C.
To maximize the largest number, use the smallest 10 distinct positive integers: 1 through 10 (sum 55).
This leaves 143−55=88 for the largest, forming a valid list (e.g., 1-9, 10, 88).
The maximum possible value is 88.
ANS = C.
