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Difficulty:
85%
(hard)
Question Stats:
49% (02:47) correct
51%
(02:49)
wrong
based on 71
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If two of the 15 smallest prime numbers are chosen at random, what is the probability that the product is a two-digit integer?
(A) \(\frac{1}{4}\)
(B) \(\frac{2}{7}\)
(C) \(\frac{29}{105}\)
(D) \(\frac{1}{3}\)
(E) \(\frac{5}{14}\)
(A) \(\frac{1}{4}\)
(B) \(\frac{2}{7}\)
(C) \(\frac{29}{105}\)
(D) \(\frac{1}{3}\)
(E) \(\frac{5}{14}\)
09 Aug 2026, 03:10
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How did you get 14 possibilities for 2? Because 2*3 = 6, which is a single digit number. So, it should be 13.
This way the probability becomes 29/105, which is certainly not among the options. So, where is the glitch?
This way the probability becomes 29/105, which is certainly not among the options. So, where is the glitch?
paragw
