Hi suntprovident,11 and
12 aren't assumptions the solution pulled from nowhere. They're just
two of the numbers already sitting in the list (4, 11, 12, 7, 1, n), and here's why every one of those numbers becomes a candidate.
Start from the conditionThe question says one basket's count
equals the average of all six. So the average has to be one of the six values in the list. That gives you six things to test - one for each basket:
- average =
4- average =
11- average =
12- average =
7- average =
1- average =
nFor each one, set (35 + n)/6 equal to that value and solve for n.
Why only some surviveSince n is a count of tomatoes, it can't be negative. Look at what the small values force:
- average =
4 -> 35 + n =
24 -> n =
-11 ❌
- average =
1 -> 35 + n =
6 -> n =
-29 ❌
Those get thrown out. That's exactly the point 2448 made: since the average is 5 + (n+5)/6, it's
always more than 5, so it can never equal
4 or
1. That's why the small numbers drop off and you're left checking
7,
11,
12, and
n.
The survivors:
- average =
7 -> n =
7 ✅
- average =
11 -> n =
31 ✅
- average =
12 -> n =
37 ✅
- average =
n -> n =
7 (same as above)
Distinct values:
7, 31, 37 -> average = 75/3 =
25.
So
11 and
12 were picked simply because they're in the list - and they
stayed because, unlike
4 and
1, they give a valid (non-negative) n.
Answer: Csuntprovident
How did you arrive at the assumption of average being 11, 12 and why only 11 and 12 ?