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Old sum= 27*55
New sum= 56*(27+3)= 56*30
Diff= sum of additional three
195= additional three
let the 1st one be M, then others are M and M+15
3M+15=195, M=60

We need to find M+15= 75 (Since the Q is asking for the box which is 15 more than each of the other two)
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Once the boxes are added and the average rises to 56, the 27 original boxes are each 1 pound “underweight “and thus in total 27 pounds underweight. Thus the new boxes are 27 pounds “overweight”and weigh a total of 56*3+27=195

If x is the weight of the heaviest of the three boxes ,

x + 2(x-15) = 195
3x = 225
X = 75

kevincan
Each of the 27 boxes in a van weighs 55 pounds. After three additional boxes are loaded into the van, the average weight of the boxes in the van is 56 pounds. If one of the three additional boxes weighs 15 pounds more than each of the other two, how much does it weigh?

A. 60 pounds
B. 65 pounds
C. 70 pounds
D. 75 pounds
E. 80 pounds
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