priyalr
To Karishma,
I'm glad you used the same approach as I've used, but I used y=1, which makes,
9x = 27^y
9x = 27
x = 3.
Look for options which give ans. as x=3, I marked A (option E also gives x=3), which gives x=3 which is wrong ans. Can u explain where I'm wrong
Thnx,
Priyal
When you put y = 1, three of the five options give you x = 3 (options A, C and E). Any one of these 3 could be the correct answer. You now need to try out some other values of y to get the answer out of these 3 options.
You need to check all the options to ensure that no other options gives you the same value. When I put y = 0, I try it in all the options and only option E gives me 1/9 so I can directly mark that as the answer.
This is the reason I mentioned the note in the post above:
"Note: If more than one options had given 1/9, you could have tried some other values to choose the right answer out of those options."
So now your next step is to put y = 0 and out of the 3 options, only E will satisfy x = 1/9.
Try and put the easiest value first. Easiest value is generally 0, if allowed.
Putting y = 2/3/4... will make it cumbersome.