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TheBigCheese
If 9x = 27^y, which of the following expresses x in terms of y?

a) 3^y
b) 3^y-1
c) 3^2y-1
d) 3^2y-3
e) 3^3y-2

9x = 27^y
x = 27^y/9
= 3^3y/3^2
= 3^(3y-2)

E
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What's wrong if i solve the problem as follows:
3*3x=3*9^y
3x = 9^y [Dividing both side by 3]
x = 3^(2y-1)
Ans. C.
Please help to correct my wrong concept as the OA is E.
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Baten80
What's wrong if i solve the problem as follows:
3*3x=3*9^y
3x = 9^y [Dividing both side by 3]
x = 3^(2y-1)
Ans. C.
Please help to correct my wrong concept as the OA is E.

The point is that \(3*9^y\) does not equal to \(27^y\): \(3*9^y=3*3^{2y}=3^{2y+1}\) on the other hand \(27^y=(3^3)^y=3^{3y}\).

Solution:
If 9x = 27^y, which of the following expresses x in terms of y?
A. 3^y
B. 3^(y-1)
C. 3^(2y-1)
D. 3^(2y-3)
E. 3^(3y-2)

\(9x=3^2*x\) and \(27^y=(3^3)^y=3^{3y}\) --> \(3^2*x=3^{3y}\) --> \(x=\frac{3^{3y}}{3^2}\) --> \(x=3^{3y-2}\).

Answer: E.

For theory on exponents check: math-number-theory-88376.html

Tough DS questions on exponents with solutions: tough-and-tricky-exponents-and-roots-questions-125967.html
Tough PS questions on exponents with solutions: tough-and-tricky-exponents-and-roots-questions-125956.html

Hope it helps.
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Baten80
What's wrong if i solve the problem as follows:
3*3x=3*9^y
3x = 9^y [Dividing both side by 3]
x = 3^(2y-1)
Ans. C.
Please help to correct my wrong concept as the OA is E.

Bunuel has already pointed out your error so I will not repeat it.

Let me give you another method of working out the solution here (though you should ensure that you understand the theory of exponents well)

If 9x = 27^y, which of the following expresses x in terms of y?
A. 3^y
B. 3^(y-1)
C. 3^(2y-1)
D. 3^(2y-3)
E. 3^(3y-2)

We need x in terms of y.
In 9x = (27)^y, put y = 0. You get x = 1/9

Now see which option will give you 1/9 when you put y = 0. I hope you can quickly see that only option (E) will give you x = 1/9 when y = 0. Answer is (E). Such methods work well when you have variables in the options.

Note: If more than one options had given 1/9, you could have tried some other values to choose the right answer out of those options.
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9x=27^y

3^2x=3^3y

devide both sides by 3^2

x=3^3y-2.

note, you need to make both sides have equale exponent, and remember when you simplify exponents through division, you subtract them
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To Karishma,

I'm glad you used the same approach as I've used, but I used y=1, which makes,
9x = 27^y
9x = 27
x = 3.
Look for options which give ans. as x=3, I marked A (option E also gives x=3), which gives x=3 which is wrong ans. Can u explain where I'm wrong

Thnx,
Priyal
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priyalr
To Karishma,

I'm glad you used the same approach as I've used, but I used y=1, which makes,
9x = 27^y
9x = 27
x = 3.
Look for options which give ans. as x=3, I marked A (option E also gives x=3), which gives x=3 which is wrong ans. Can u explain where I'm wrong

Thnx,
Priyal

When you put y = 1, three of the five options give you x = 3 (options A, C and E). Any one of these 3 could be the correct answer. You now need to try out some other values of y to get the answer out of these 3 options.

You need to check all the options to ensure that no other options gives you the same value. When I put y = 0, I try it in all the options and only option E gives me 1/9 so I can directly mark that as the answer.
This is the reason I mentioned the note in the post above:
"Note: If more than one options had given 1/9, you could have tried some other values to choose the right answer out of those options."

So now your next step is to put y = 0 and out of the 3 options, only E will satisfy x = 1/9.
Try and put the easiest value first. Easiest value is generally 0, if allowed.

Putting y = 2/3/4... will make it cumbersome.
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

*New project from GMAT Club!!! Check HERE

Theory on Exponents: math-number-theory-88376.html

All DS Exponents questions to practice: search.php?search_id=tag&tag_id=39
All PS Exponents questions to practice: search.php?search_id=tag&tag_id=60

Tough and tricky DS exponents and roots questions with detailed solutions: tough-and-tricky-exponents-and-roots-questions-125967.html
Tough and tricky PS exponents and roots questions with detailed solutions: tough-and-tricky-exponents-and-roots-questions-125956.html
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

*New project from GMAT Club!!! Check HERE

Theory on Exponents: math-number-theory-88376.html

All DS Exponents questions to practice: search.php?search_id=tag&tag_id=39
All PS Exponents questions to practice: search.php?search_id=tag&tag_id=60

Tough and tricky DS exponents and roots questions with detailed solutions: tough-and-tricky-exponents-and-roots-questions-125967.html
Tough and tricky PS exponents and roots questions with detailed solutions: tough-and-tricky-exponents-and-roots-questions-125956.html

9x=27^y
3^2 x = 3^3y

Clearly, x=1 an y=2/3 will satisfy

Now we have the values of x given in the options, substitute y=2/3 , wherever we get value =1, is the answer

which is clearly E since only that has 3 multiplied with y which conveniently cancels our denominator and results in 3^0 =1

Ans=>E
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27 can be written as 9^ 3/2

So x = 9^(3y/2-1)

x = 3^(3y-2) = Answer = E
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\((3)^{2}\)x= \((3)^{3y}\)

So x= \((3)^{3y}\)/\((3)^{2}\)

x= \((3)^{3y-2}\)

Answer: E.

Kudos please if you like my explanation!
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TheBigCheese
If \(9x = 27^y\), which of the following expresses x in terms of y?

A. \(3^y\)

B. \(3^{(y-1)}\)

C. \(3^{(2y-1)}\)

D. \(3^{(2y-3)}\)

E. \(3^{(3y-2)}\)

Let’s simplify the given equation:

9x = 27^y

(3^2)x = 3^(3y)

x = 3^(3y)/3^2

x = 3^(3y-2)

Answer: E
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