If the average (arithmetic mean) of five consecutive negative integers

Question

If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined

Mikko · Answer

Do we need to know the Average is even or odd to find the range of these 5 neg consecutives?

And Even the five are neg or not, the range is always 4.

manojgmat · Answer

numbers will be 2k-3, 2k-2, 2k-1, 2k, 2k+1
range = 2k+1 - 2k+3 = 4

tejal777 · Answer

Def. sleep deprived when I was doing the question :shock:

Sorry got thrown off by the negative integer thing..

amit2k9 · Answer

5 consecutive numbers means difference between first and the last integer = 4

ScottTargetTestPrep · Answer

We are asking for the range of the 5 consecutive integers. It’s a fact that the range of a set of n integers is always n - 1. For example, in the set of {2, 3, 4, 5, 6, 7}, there are 6 consecutive integers, we see that the range is 7 - 2 = 5, which is 1 less than the number of consecutive integers. Therefore, in a set of 5 consecutive integers, whether they be positive or negative, the difference between the greatest and least integers, i.e., the range, is 4.

Answer: A

BrentGMATPrepNow · Answer

Let  x  = the 1st (smallest integer)
So, x+1 = the 2nd integer
 x+2 = the 3rd integer
 x+3 = the 4th integer
  x+4  = the 5th integer (greatest integer)

What is the difference between the greatest and least of the five integers?   
Difference = (  x+4 ) -  x  = 4

Answer: A

Cheers,
Brent

Archit3110 · Answer

sum of 5 consective no 
5a+10 = 10k-5
a= 2k-3
so largest no ; 4+2k-3
differnrence 
4+2k-3-2k+3 = 4
IMO A

takozzz · Answer

Let's say A is the greatest number, B is the least number. 
because they are five consecutive numbers, we can get(A+B)/2=2k-1, A+B=4k-2
Because they are negative integer, so A+B must be negative, we give K=-1, then A+B=-6, which means A=-1,B=-5
The difference between the greatest number and the least number is A-B=-1-(-5)=4

Abhishek009 · Answer

Let, The 5 numbers be  ( 2k – 3 ) , ( 2k – 2 ) , ( 2k – 1 ) , ( 2k ) , ( 2k + 1 )

( 2k + 1 ) - ( 2k - 3 ) = 4 , Answer must be (A)

ScottTargetTestPrep · Answer

The difference between the greatest and least of any five consecutive integers is 4, regardless whether the integers are positive or negative.

Answer: A

COolguy101 · Answer

Sir, if these numbers are like -1,-3,-5,-7 and -9, I did not see the range is 4, actually range is 8 here, How can we surely say like this ?

BrushMyQuant · Answer

Given that the average (arithmetic mean) of five consecutive negative integers is 2k – 1 and we need to find the difference between the greatest and least of the five integers

Let the five numbers be x-2, x-1, x , x+1, x+2

Difference between the highest and the lowest number = (x+2) - (X-2) = x + 2 - x + 2 = 4

So,  Answer will be A .
Hope it helps!

Watch the following video to Learn the Basics of Statistics

https://www.youtube.com/watch?v=Cvy_HHw4KIs

If the average (arithmetic mean) of five consecutive negative integers

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