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EnterMatrix
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In May, Xiang sold 15 used cars. For these 15 cars, the Sat Jul 17, 2010 10:18 am
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88% (01:43) correct 12% (02:25) wrong based on 716 sessions

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In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $6,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?

1. $15,600
2. $15,750
3. $16,820
4. $18,100
5. $19,200
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D
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Bunuel
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In May, Xiang sold 15 used cars. For these 15 cars, the Sat Jul 17, 2010 3:33 pm
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EnterMatrix
In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $6,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?

1. $15,600
2. $15,750
3. $16,820
4. $18,100
5. $19,200
Show more

Edited the question as there was a typo.

Range = Highest Value - Lowest Value.

Range in May was 15,000 and the lowest price in May was 4,500, thus the highest price in May was 15,000+4,500=19,500.
Range in June was 16,500 and the lowest price in June was 6,100, thus the highest price in June was 16,500+6,100=22,600.

Lowest price of a car in May-June was 4,500 (May) and the highest price of a car in May-June was 22,600, thus the range for May-June is 22,600-4,500=18,100.

Answer: D.
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In May, Xiang sold 15 used cars. For these 15 cars, the Sun Jul 18, 2010 1:17 am
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Cool...that works!
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In May, Xiang sold 15 used cars. For these 15 cars, the Sun Sep 18, 2016 6:35 pm
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Thank you for posting the solution although I am a bit confused. What is your reasoning for adding the selling price of the highest and lowest cars to get the highest price? They're the selling prices of 2 different cars. Why wouldn't the highest price just be... the highest price for each month? Thank you!
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Hyper1on89
Thank you for posting the solution although I am a bit confused. What is your reasoning for adding the selling price of the highest and lowest cars to get the highest price? They're the selling prices of 2 different cars. Why wouldn't the highest price just be... the highest price for each month? Thank you!
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For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500:

Range = Highest Value - Lowest Value.
15,000 = Highest Value - 4,500.
Highest Value = 15,000 + 4,500 = 19,500.
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In May, Xiang sold 15 used cars. For these 15 cars, the Mon Sep 19, 2016 4:41 am
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Quote:
For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500:

Range = Highest Value - Lowest Value.
15,000 = Highest Value - 4,500.
Highest Value = 15,000 + 4,500 = 19,500.
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Thank you, Bunuel. Makes sense now.
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In May, Xiang sold 15 used cars. For these 15 cars, the Fri Sep 25, 2020 1:07 pm
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EnterMatrix
In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $6,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?

1. $15,600
2. $15,750
3. $16,820
4. $18,100
5. $19,200
Show more
Solution:

The highest selling price of the cars sold in May was 4,500 + 15,000 = $19,500, and the highest selling price of the cars sold in June was 6,100 + 16,500 = $22,600. Therefore, the highest selling price of the cars sold in these two months was $22,600. Since the lowest selling price of the cars sold in the same two months was $4,500, the range was 22,600 - 4,500 = $18,100.

Answer: D
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A common enough question based on Range.

Range = Highest Value - Smallest Value

In the sum above, we know that the lowest value = Min(4500, 6100) = 4500

Largest Value = Range + Smallest Value

The largest Value = Max(15000 + 4500, 16500 + 6100) = Max(19500, 22600) = 22600

The range of the 25 cars = 22600 - 4500 = 18100


Option D

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