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Updated on: 05 Jan 2015, 04:15
Originally posted by anuragsingal on 11 Sep 2010, 04:53.
Last edited by Bunuel on 05 Jan 2015, 04:15, edited 1 time in total.
Last edited by Bunuel on 05 Jan 2015, 04:15, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
78% (01:16) correct
22%
(01:18)
wrong
based on 281
sessions
History
Date
Time
Result
Not Attempted Yet
n is the product of least and greatest 6 consecutive integers. What is n?
(1) The greatest integer is 20
(2) The average arithmetic mean of 6 consecutive integers is 17.5
Solution:
(1) The greatest integer is 20
(2) The average arithmetic mean of 6 consecutive integers is 17.5
Solution:
If n is the product of the least and the greatest of 6 consecutive integers, what is the value of n?
What do we know? We have a list of 6 consecutive integers. So, if we can determine which integers make up our list, we can certainly answer the question.
(1) the greatest integer in the list is 20
Well, if we know the biggest number on the list we can certainly count backwards to determine the other 5: sufficient.
(2) the average (arithmetic mean) of the integers is 17.5
Since our numbers are consecutive, we can certainly use this information to figure out exactly what the list is: sufficient.
If we needed to actually do so, we could:
1) know that for a set of consecutive numbers, mean = median. Since we have an even number of terms, the median is the average of the two middle terms, so the two middle terms in our set must be 17 and 18, which we can then expand to {15, 16, 17, 18, 19, 20}; or
2) use the average formula.
Average = (sum of terms)/(# of terms)
17.5 = (t1 + t2 + t3 + t4 + t5 + t6)/6
105 = t1 + t2 + t3 + t4 + t5 + t6
And, since our terms are consecutive, we know that:
t1 + t2 + t3 + t4 + t5 + t6 = t1 + (t1 + 1) + (t1 + 2) + (t1 + 3) + (t1 + 4) + (t1 + 5)
so
105 = 6(t1) + 15
90 = 6(t1)
15 = t1
so our set must be {15, 16, 17, 18, 19, 20}
Lots of other tricks we could use to also figure out the exact set.
Each of (1) and (2) is sufficient alone: choose D.
What do we know? We have a list of 6 consecutive integers. So, if we can determine which integers make up our list, we can certainly answer the question.
(1) the greatest integer in the list is 20
Well, if we know the biggest number on the list we can certainly count backwards to determine the other 5: sufficient.
(2) the average (arithmetic mean) of the integers is 17.5
Since our numbers are consecutive, we can certainly use this information to figure out exactly what the list is: sufficient.
If we needed to actually do so, we could:
1) know that for a set of consecutive numbers, mean = median. Since we have an even number of terms, the median is the average of the two middle terms, so the two middle terms in our set must be 17 and 18, which we can then expand to {15, 16, 17, 18, 19, 20}; or
2) use the average formula.
Average = (sum of terms)/(# of terms)
17.5 = (t1 + t2 + t3 + t4 + t5 + t6)/6
105 = t1 + t2 + t3 + t4 + t5 + t6
And, since our terms are consecutive, we know that:
t1 + t2 + t3 + t4 + t5 + t6 = t1 + (t1 + 1) + (t1 + 2) + (t1 + 3) + (t1 + 4) + (t1 + 5)
so
105 = 6(t1) + 15
90 = 6(t1)
15 = t1
so our set must be {15, 16, 17, 18, 19, 20}
Lots of other tricks we could use to also figure out the exact set.
Each of (1) and (2) is sufficient alone: choose D.
11 Sep 2010, 04:55
Kudos
Bookmarks
Hi anurag,
Could you please change the colour of the font. For some reason the top part shows yellow....Maybe its only in my system.
Thanks.
Could you please change the colour of the font. For some reason the top part shows yellow....Maybe its only in my system.
Thanks.
11 Sep 2010, 04:57
Kudos
Bookmarks
106. n is the product of least and greatest 6 consecutive integers. What is n?
1) the greatest integer is 20
2) the average arithmetic mean of 6 consecutive integers is 17.5
Solution:
If n is the product of the least and the greatest of 6 consecutive integers, what is the value of n?
What do we know? We have a list of 6 consecutive integers. So, if we can determine which integers make up our list, we can certainly answer the question.
(1) the greatest integer in the list is 20
Well, if we know the biggest number on the list we can certainly count backwards to determine the other 5: sufficient.
(2) the average (arithmetic mean) of the integers is 17.5
Since our numbers are consecutive, we can certainly use this information to figure out exactly what the list is: sufficient.
If we needed to actually do so, we could:
1) know that for a set of consecutive numbers, mean = median. Since we have an even number of terms, the median is the average of the two middle terms, so the two middle terms in our set must be 17 and 18, which we can then expand to {15, 16, 17, 18, 19, 20}; or
2) use the average formula.
Average = (sum of terms)/(# of terms)
17.5 = (t1 + t2 + t3 + t4 + t5 + t6)/6
105 = t1 + t2 + t3 + t4 + t5 + t6
And, since our terms are consecutive, we know that:
t1 + t2 + t3 + t4 + t5 + t6 = t1 + (t1 + 1) + (t1 + 2) + (t1 + 3) + (t1 + 4) + (t1 + 5)
so
105 = 6(t1) + 15
90 = 6(t1)
15 = t1
so our set must be {15, 16, 17, 18, 19, 20}
Lots of other tricks we could use to also figure out the exact set.
Each of (1) and (2) is sufficient alone: choose D.
1) the greatest integer is 20
2) the average arithmetic mean of 6 consecutive integers is 17.5
Solution:
If n is the product of the least and the greatest of 6 consecutive integers, what is the value of n?
What do we know? We have a list of 6 consecutive integers. So, if we can determine which integers make up our list, we can certainly answer the question.
(1) the greatest integer in the list is 20
Well, if we know the biggest number on the list we can certainly count backwards to determine the other 5: sufficient.
(2) the average (arithmetic mean) of the integers is 17.5
Since our numbers are consecutive, we can certainly use this information to figure out exactly what the list is: sufficient.
If we needed to actually do so, we could:
1) know that for a set of consecutive numbers, mean = median. Since we have an even number of terms, the median is the average of the two middle terms, so the two middle terms in our set must be 17 and 18, which we can then expand to {15, 16, 17, 18, 19, 20}; or
2) use the average formula.
Average = (sum of terms)/(# of terms)
17.5 = (t1 + t2 + t3 + t4 + t5 + t6)/6
105 = t1 + t2 + t3 + t4 + t5 + t6
And, since our terms are consecutive, we know that:
t1 + t2 + t3 + t4 + t5 + t6 = t1 + (t1 + 1) + (t1 + 2) + (t1 + 3) + (t1 + 4) + (t1 + 5)
so
105 = 6(t1) + 15
90 = 6(t1)
15 = t1
so our set must be {15, 16, 17, 18, 19, 20}
Lots of other tricks we could use to also figure out the exact set.
Each of (1) and (2) is sufficient alone: choose D.
