Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
24 Jan 2011, 01:01
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
34% (01:55) correct
66%
(01:25)
wrong
based on 62
sessions
History
Date
Time
Result
Not Attempted Yet
If c and k are distinct positive integers, is c divisible by k?
(1) \(2k > c\)
(2) \((k^2 + k)= c\)
(1) \(2k > c\)
(2) \((k^2 + k)= c\)
This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
Looking for better-quality questions? Check out the 'Similar Questions' block below
for a list of similar but high-quality questions.
Want to join other relevant Problem Solving discussions? Visit our Data Sufficiency (DS) Forum
for the most recent and top-quality discussions.
Thank you for understanding, and happy exploring!
24 Jan 2011, 03:02
Kudos
Bookmarks
gmatpapa
Note that an integer \(a\) is a multiple of an integer \(b\) (integer \(a\) is a divisible by an integer \(b\)) means that \(\frac{a}{b}=integer\).
Given: \(c\) and \(k\) are distinct positive integers. Question: is \(\frac{c}{k}=integer\)? Now, \(c\) and \(k\) are distinct so if \(c\) is indeed divisible by \(k\) then \(\frac{c}{k}\) can ONLY be 2, 3, 4, ... basically any positive integer except 1 (again as \(c\) and \(k\) are distinct and positive).
(1) \(2k > c\) --> divide both sides of the inequality by \(k\) (we can safely do this as given that \(k\) is positive) --> \(2>\frac{c}{k}\) --> \(c\) is not divisible by \(k\). Sufficient.
(2) \((k^2 + k)= c\) --> \(k(k+1)=c\) --> \(\frac{c}{k}=k+1=integer\) --> \(c\) is divisible by \(k\). Sufficient.
Now, technically answer should be D, as EACH statement ALONE is sufficient to answer the question.
But even though formal answer to the question is D (EACH statement ALONE is sufficient), this is not a realistic GMAT question, as: on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other.
So we can not have answer NO from statement (1) and answer YES from statement (2), as in this case statements would contradict each other.
Hope it's clear.
24 Jan 2011, 03:38
Kudos
Bookmarks
Yes! I could figure out how statement 2 was sufficient (same logic as you demonstrated) and now I can see statement 1 more clearly. Thanks!
This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
Looking for better-quality questions? Check out the 'Similar Questions' block below
for a list of similar but high-quality questions.
Want to join other relevant Problem Solving discussions? Visit our Data Sufficiency (DS) Forum
for the most recent and top-quality discussions.
Thank you for understanding, and happy exploring!
