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30 Jan 2011, 06:18
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
60% (01:14) correct
40%
(01:39)
wrong
based on 418
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In the figure above, what is the product of the lengths of AD and BC?
(1) The product of the lengths of AC and BE is 60.
(2) The length of BC is 8.
Attachment:
triangle.png [ 2.62 KiB | Viewed 8708 times ]
30 Jan 2011, 06:31
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In the figure above, what is the product of the lengths of AD and BC?
Question: BC*AD=? Note that AD is perpendicular to BC and BE is perpendicular to AC. So: \(\frac{BC*AD}{2}=\frac{base*height}{2}=area\) and similarly \(\frac{AC*BE}{2}=\frac{base*height}{2}=area\) --> \(\frac{BC*AD}{2}=\frac{AC*BE}{2}\) --> \(BC*AD=AC*BE\).
(1) The product of the lengths of AC and BE is 60 --> AC*BE=60=BC*AD. Sufficient.
(2) The length of BC is 8. Not sufficient.
Answer: A.
General Discussion
jlgdr
Joined: 06 Sep 2013
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Concentration: Finance
Schools: Wharton '17 (A) HBS '17 (WA$)
10 Jan 2014, 14:28
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fluke
Yes one should keep in mind that a triangle of this type has three heights and three bases so one can calculate the area with any of those two perpendicular measures. Hence BC*AC / 2 = AC*BE /2
Hence A
