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19 Jun 2011, 08:02
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (01:13) correct
24%
(01:58)
wrong
based on 108
sessions
History
Date
Time
Result
Not Attempted Yet
What is the volume of rectangular box Q?
(1) Two adjacent faces of the box Q have areas 10 and 12.
(2) Two opposite faces of box Q each have an area of 30.
(1) Two adjacent faces of the box Q have areas 10 and 12.
(2) Two opposite faces of box Q each have an area of 30.
19 Jun 2011, 10:14
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guygmat
Volume = l*b*h
st 1: 2 adjacent face has area of 10, 12
so the face can be 10,12,1 or 2, 5,6 ..each case the answer is different
hence in sufficicent
st 2: opposite faces have an area of 30... clearly insufficient
1 and 2 together
l^2b^2c^2 = 10*12*30
lbh = sqrt(10*12*30)
= 60
hence sufficient
20 Jun 2011, 07:39
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[list=]=>[/list]consider a rectangle box with sides \(x,y,z\)
rephrase the question-- what is\(xyz ?\)
statement 1 :
suppose \(xy=10,xz=12\) can we find out \(xyz ?\) no
combining \(xy\) and \(xz\) === \(xy^2z=120\)
so 1 insuff
statement 2:
suppose \(xy/yz/xz=30\)
still cannot find xyz
2 insuff
combine 1 & 2
\(xy=10,xz=12 & yz=30\)
so \((xyz)^2=3600\) =:> \(xyz=60\)
so answer is C
i hope it helps
rephrase the question-- what is\(xyz ?\)
statement 1 :
suppose \(xy=10,xz=12\) can we find out \(xyz ?\) no
combining \(xy\) and \(xz\) === \(xy^2z=120\)
so 1 insuff
statement 2:
suppose \(xy/yz/xz=30\)
still cannot find xyz
2 insuff
combine 1 & 2
\(xy=10,xz=12 & yz=30\)
so \((xyz)^2=3600\) =:> \(xyz=60\)
so answer is C
i hope it helps
