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Updated on: 08 Dec 2018, 20:42
Originally posted by Jasontuyj2012 on 06 Aug 2011, 04:46.
Last edited by GMATBusters on 08 Dec 2018, 20:42, edited 1 time in total.
Last edited by GMATBusters on 08 Dec 2018, 20:42, edited 1 time in total.
Edited the OA
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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52% (02:30) correct
48%
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In the figure above, QRS is a straight line and line TR bisects PRS, Is it true that lines TR and PQ are parallel?
(1) PQ = PR
(2) QR = PR
Attachment:
File comment: See attached
123.jpg [ 12.66 KiB | Viewed 10380 times ]
123.jpg [ 12.66 KiB | Viewed 10380 times ]
06 Aug 2011, 18:25
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To prove that both lines are parallel we need to prove that angle PQR is equal to angle TRS.
statement 1 says)PQ=PR , so angle PQR and angle PRQ are equal. let them be equal to x. Then angle QPR = 180-2x and exterior angle PRS = x+ 180 -2x , so angle PRS = 180-x. TR is bisector of angle angle PRS so angle TRS = half of angle PRS. so angle TRS - 90 -x/2. from this we cant conclude weather 90 -x/2 = x or not. so insufficient.
statement 2 says QR=PR, so angle angle PQR = angle QPR, AND FROM PROPERTY OF EXTERIOR ANGLE =SUM OF TWO INTERIOR ANGLE WE KNOW. angle PRS = angle PQR +angle QPR . so angle TRS = half of angle PRS = angle PQR. so suffiecient. both lines are parallel.
Answer B
statement 1 says)PQ=PR , so angle PQR and angle PRQ are equal. let them be equal to x. Then angle QPR = 180-2x and exterior angle PRS = x+ 180 -2x , so angle PRS = 180-x. TR is bisector of angle angle PRS so angle TRS = half of angle PRS. so angle TRS - 90 -x/2. from this we cant conclude weather 90 -x/2 = x or not. so insufficient.
statement 2 says QR=PR, so angle angle PQR = angle QPR, AND FROM PROPERTY OF EXTERIOR ANGLE =SUM OF TWO INTERIOR ANGLE WE KNOW. angle PRS = angle PQR +angle QPR . so angle TRS = half of angle PRS = angle PQR. so suffiecient. both lines are parallel.
Answer B
08 Dec 2018, 16:50
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Jasontuyj2012
It seems the answer is supposed to be "B" and not "A"
