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505-555 (Easy)|   Exponents|   Number Properties|   Roots|                        
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[quote="Bunuel"]If m and n are positive integers, is \((\sqrt{m})^n\) an integer?

(1) \(\sqrt{m}\) is an integer.
(2) \(\sqrt{n}\) is an integer.

1) √m = Ineteger
i.e. \((\sqrt{m})^n = Integer^{Integer} \)
But \(Integer^{Integer} = Integer\)
SUFFICIENT

2)√n = integer does not confirm whether n is even (Yes) or not (No) hence
NOT SUFFICIENT

Answer: Option A
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If m and n are positive integers, is \((\sqrt{m})^n\) an integer?

(1) \(\sqrt{m}\) is an integer.

\(Integer^{integer}\) = integer. SUFFICIENT.

(2) \(\sqrt{n}\) is an integer.

We can get a yes and no answer here because we don't know if \(\sqrt{m}\) is an integer. INSUFFICIENT.

Answer is A.
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Bunuel
If m and n are positive integers, is \((\sqrt{m})^n\) an integer?

(1) \(\sqrt{m}\) is an integer.
(2) \(\sqrt{n}\) is an integer.

Diagnostic Test
Question: 44
Page: 26
Difficulty: 600


here we know both m and n are positive integers


we need to find if this is an integer
\((\sqrt{m})^n\)



Lets look at statement 1

root m is an integer

so we know (int)^(int) is an integer

So this is sufficient as (root m)^n is an integer according to this


Looking at st 2 we know that root n is integer but this statement doesnt help as we know nothing about root m'

so this st is insufficient


Answer (A)
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