First of all thank you members,
But little confusion still remains, as long as I see this sum in isolation everything is clear but when I try and relate this sum to this sum given below I get a bit confused.
What is the ratio of x:y:z? (
what-is-the-ratio-of-x-y-z-56282.html#p400899 )
(1) xy = 14
(2) yz = 21
now in this sum individually obviously both are insufficient
but when we take them together, expressing everything in terms of y
\(x = \frac {14}{y}\)
\(z =\frac {21}{y}\)
\(so \,x:y:z = \frac {\frac{\frac{14}{y}}{y}}{\frac{21}{y}}\)
\(so \, for \, Y=1 \to x:y:z =\frac {\frac{14}{1}}{21}\)
and
\(for \, Y=7 \to x:y:z =\frac {\frac{2}{7}}{3}\)
now using the same logic as above where we said "a reduces" and said that the ratio remains the same, can't we say in this sum too that ( x:y:z ) "Y reduces" hence 1+2 is sufficient to answer the ratio of x:y:z ?
if in a:b:c sum we say " as a:b:c = 2:8:5 = 4:16:10 = 8:32:20 ... " meaning in all the cases ratio is same
why in x:y:z = 14:1:21 and x:y:z = 2:7:3 , we are taking ratio to be different? shouldn't the ratio be same whether x:y:z= 14:1:21 or x:y:z = 2:7:3
we can say Y can be reduced and that 14:1:21 is the same as 2:7:3 answer should be C in this x:y:z sum, still here the answer is E. ?? Am I messing up something? Thanks.
Edit: my bad didn't see that 14:1:21 cannot be reduced to 2:7:3 so of course the answer is E