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11 Sep 2013, 05:20
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D
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At a fair, tickets for rides cost 50 cents each. If Tim spent all the money he had with him for these tickets, how many ride tickets did he buy?
1) If the cost of tickets had been 60 cents, he could have bought exactly 10 tickets, with no money left over.
2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over.
1) If the cost of tickets had been 60 cents, he could have bought exactly 10 tickets, with no money left over.
2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over.
What are the equations for each statement?
11 Sep 2013, 05:25
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At a fair, tickets for rides cost 50 cents each. If Tim spent all the money he had with him for these tickets, how many ride tickets did he buy?
Say Tim had x cents. We should find the value of x/50.
(1) If the cost of tickets had been 60 cents, he could have bought exactly 10 tickets, with no money left over --> x/60=10 --> x=600 cents --> x/50=12. Sufficient.
(2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over --> (x+50)/50=13 --> x=600 cents --> x/50=12. Sufficient.
Or: 50 cents is for 1 ticket, so without these 50 cents he can buy 1 less, so 12 tickets.
Answer: D.
Say Tim had x cents. We should find the value of x/50.
(1) If the cost of tickets had been 60 cents, he could have bought exactly 10 tickets, with no money left over --> x/60=10 --> x=600 cents --> x/50=12. Sufficient.
(2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over --> (x+50)/50=13 --> x=600 cents --> x/50=12. Sufficient.
Or: 50 cents is for 1 ticket, so without these 50 cents he can buy 1 less, so 12 tickets.
Answer: D.
13 Sep 2013, 08:12
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Why are we dividing by 50 in the second equation?
