Last visit was: 24 Apr 2026, 08:11 It is currently 24 Apr 2026, 08:11
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
avatar
Pmar2012
Joined: 23 Jan 2013
Last visit: 27 Apr 2015
Posts: 6
Own Kudos:
241
 [109]
Given Kudos: 4
Posts: 6
Kudos: 241
 [109]
5
Kudos
Add Kudos
104
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,814
Own Kudos:
Given Kudos: 105,871
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,814
Kudos: 811,014
 [45]
23
Kudos
Add Kudos
22
Bookmarks
Bookmark this Post
General Discussion
User avatar
WholeLottaLove
Joined: 13 May 2013
Last visit: 13 Jan 2014
Posts: 301
Own Kudos:
640
 [2]
Given Kudos: 134
Posts: 301
Kudos: 640
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
DJ1986
Joined: 05 Jul 2015
Last visit: 16 May 2016
Posts: 51
Own Kudos:
232
 [2]
Given Kudos: 3
Concentration: Real Estate, International Business
GMAT 1: 600 Q33 V40
GPA: 3.3
GMAT 1: 600 Q33 V40
Posts: 51
Kudos: 232
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Easy solution:

A) Obviously sufficient because a^2+b^2=c^2

B) The white to gray is 2:1 so the gray is 1/3 of the total area. The area is 4*4. So the missing line segment is (4/3).

ANS: D
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,063
Own Kudos:
20,000
 [1]
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,063
Kudos: 20,000
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Points M and P lie on square LNQR, and LM = PQ. What is the length of the line segment PQ?

(1) PR=410 − − √ 3
(2) The ratio of the area of the unshaded region to the total area of the shaded region is 2 to 1.

We can know PQ if we know PR, so there is one variable (PR), and 2 equations are given by the conditions, so there is high chance (D) will be the answer.
For condition 1, from (4 sqrt 10/3)^2-4^2=PQ^2. PQ=4/3. This is sufficient
For condition 2, if the ratio of the area is 2:1, the height is the same, so NP:PQ=2:1, and PQ=4/3 so this is sufficient as well, and the answer becomes (D).

For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
User avatar
mbaapp1234
Joined: 23 Dec 2013
Last visit: 05 Jul 2019
Posts: 81
Own Kudos:
90
 [2]
Given Kudos: 23
Location: United States (CA)
GMAT 1: 710 Q45 V41
GMAT 2: 760 Q49 V44
GPA: 3.76
Products:
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Pmar2012
Attachment:
Untitled2.png
Points M and P lie on square LNQR, and LM = PQ. What is the length of the line segment PQ?

(1) \(PR=\frac{4\sqrt{10}}{3}\)
(2) The ratio of the area of the unshaded region to the total area of the shaded region is 2 to 1.

The goal is to find then length of PQ.

Statement 1) PR = 4sqrt(10)/3

By the Pythagorean theorem, we can determine that x^2 + 4^2 = 16/9*10

x^2 = 160/9-16

x^2 = 17.77-16

Sufficient.

Statement 2) The ratio of the area of the unshaded region to the total area of the shaded region is 2 to 1.

Let PQ = x

The area of the shaded region is 2(1/2*4*x) = 4x

The total area of the square is 4^2 = 16

16 - 4x = unshaded

(16-4x)/(4x) = 2/1

16-4x = 8 x

16 = 12x
4 = 3x
4/3 = x

Sufficient.
User avatar
CAMANISHPARMAR
Joined: 12 Feb 2015
Last visit: 13 Mar 2022
Posts: 1,016
Own Kudos:
Given Kudos: 77
Posts: 1,016
Kudos: 2,552
Kudos
Add Kudos
Bookmarks
Bookmark this Post
St1:- Apply pythagoras theorem as the lengths of two sides are given and one is missing.

St2:- Apply the formula for area of a triangle formula to find the length of the side.

Option D is the correct answer
User avatar
davidbeckham
User avatar
Stanford School Moderator
Joined: 11 Jun 2019
Last visit: 11 Oct 2021
Posts: 109
Own Kudos:
Given Kudos: 181
Location: India
Products:
Posts: 109
Kudos: 68
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Bunuel, please could you explain the highlighted part again?

Bunuel

Points M and P lie on square LNQR, and LM = PQ. What is the length of the line segment PQ?

(1) \(PR=\frac{4\sqrt{10}}{3}\). We know two sides (PR and PQ) in right triangle PQR, thus we can find the third side PQ. Sufficient.

(2) The ratio of the area of the unshaded region to the total area of the shaded region is 2 to 1. Say LM = PQ = x, then the area of the shaded region is 2*(1/2*4*x)=4x. The area of unshaded region is 4*4-4x=16-4x. Thus we have that (unshaded)/(shaded)=(16-4x)/4x=2/1. We can find x. Sufficient.

Answer: D.
User avatar
CrackverbalGMAT
User avatar
Major Poster
Joined: 03 Oct 2013
Last visit: 24 Apr 2026
Posts: 4,846
Own Kudos:
9,182
 [1]
Given Kudos: 226
Affiliations: CrackVerbal
Location: India
Expert
Expert reply
Posts: 4,846
Kudos: 9,182
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Statement 1: The length of the sides PR and QR are given. Since PQR is a right triangle , we can find the third side PQ. Hence Statement 1 is sufficient.
Statement 2:
The ratio of the area of the unshaded region to the total area of the shaded region is 2 to 1.
Since we know the total area of the square ( 4 * 4) , we can find the total area of the shaded region by using the ratios.

Total area of shaded region = 1/3 *( Area of the square)

Lets consider 2 triangles , MLR and PQR

Area of triangle = ½ * base* height
Its given that LM = PQ,
So the base and height of triangle MLR and PQR are the same.
Thus, Area of triangle MLR = Area of triangle PQR

Area of triangle PQR = ½ (Area of total shaded region)
Once you know the area of PQR, we can easily find the length of PQ.
Area of PQR = ½ * QR * PQ =½ * 4 * PQ
Hence Statement 2 is sufficient.

Option D is the answer

Thanks,
Clifin J Francis
GMAT SME
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,972
Own Kudos:
Posts: 38,972
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109814 posts
498 posts
212 posts