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Bunuel
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Hi Bunuel,

I didnt get the second point, why is it sufficient to answer the question??
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Hi Bunuel,

I didnt get the second point, why is it sufficient to answer the question??

The question asks whether (total age) < 600x. (2) says that (total age) = 600x, thus the answer to the question is NO.
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Hi,

I chose B for the same reasons, but now I have a question...

[1] Does not give us the number of employees, as these are 3x+4x+8x=15x.
[2] Gives us 40*3x+20*4x+50*8x=600x.

So, all sounds logical. But now I thought of this for [1] and got confused:

We know that 3x+4x+8x=15x is N (Number of emloyees).
And we know that the sum of the ages is 600.

Can we say then than \(Mage =\) \(\frac{Sage}{N}\) ??

Then, this could become \(M =\)\(\frac{600}{15x}\)


\(x =\) \(\frac{600}{15M}\)

\(x = 40M\)

I am sorry for not being clear, but I barely understand myself at this point... Any ideas about what is confusing me?
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The average age employees in X, Y, and Z, is 40, 20, and 50, respectively. (total age)=40*3x+20*4x+50*8x=600x, so the answer to the question is NO.

B Sufficient.
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­x: number of employees in company X
y: number of employees in company Y
z: number of employees in company Z

x:y:z
3:4:8
=> x + y + z = (3+4+8)k = 15k

a: average age of employees in company X
b: average age of employees in company Y
c: average age of employees in company Z

Question: \(\frac{a*3k + b*4k + c*8k}{15k} < 40\)?

=> 3a + 4b + 8c < 600?

Statement 1: ax + by + cz = 600

=> Insufficient

Statement 2: a = 40, b = 20, c = 50

=> 3a + 4b + 8c = 3 * 40 + 4* 20 + 8 * 50
=> can be compared with 600

=> Sufficient

==> Answer is B­
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Let me clarify what's happening with Statement 1.

Your Confusion: You're trying to use the total age (600) to somehow determine the average age.

The Key Insight: In Statement 1, we have:
- Total employees = 15x
- Total age = 600 years
- Average age = 600/15x = 40/x

The Problem: We don't know x! And different values of x give different average ages.

Let me prove this with examples:

Case 1: If x = 2
- Total employees = 15(2) = 30
- Average age = 600/30 = 20 years
- Is 20 < 40? YES

Case 2: If x = 1
- Total employees = 15(1) = 15
- Average age = 600/15 = 40 years
- Is 40 < 40? NO

Both cases satisfy Statement 1 (total age = 600), but give different answers to our question!

Your algebra attempt: When you wrote x = 40/M, you were essentially saying "if I knew the average age M, I could find x." That's true! But Statement 1 doesn't tell us the average age - that's exactly what we're trying to find!

DS Principle: A statement is sufficient only when it gives ONE definitive answer, not when it "could" give an answer.

Statement 2, however: Tells us the exact average ages in each company, so we can calculate:
Average age = (3x×40 + 4x×20 + 8x×50)/(15x) = 600x/15x = 40

This is exactly 40, not less than 40, regardless of the value of x.

Answer: B

pacifist85
Hi,

I chose B for the same reasons, but now I have a question...

[1] Does not give us the number of employees, as these are 3x+4x+8x=15x.
[2] Gives us 40*3x+20*4x+50*8x=600x.

So, all sounds logical. But now I thought of this for [1] and got confused:

We know that 3x+4x+8x=15x is N (Number of emloyees).
And we know that the sum of the ages is 600.

Can we say then than \(Mage =\) \(\frac{Sage}{N}\) ??

Then, this could become \(M =\)\(\frac{600}{15x}\)


\(x =\) \(\frac{600}{15M}\)

\(x = 40M\)

I am sorry for not being clear, but I barely understand myself at this point... Any ideas about what is confusing me?
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