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Bunuel
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Alternate method:

Let number of exams = x = 10
average = y = 50

Question: Is (500 + z)/11 = 75?

St1: x = 3y --> Clearly insufficient as we do not know anything about z.

St2: z = (xy + 3y)/2 = (500 + 150)/2
We know the value of z.
Sufficient.

Answer: B
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Bunuel

Tough and Tricky questions: Statistics



The average score of x number of exams is y. When an additional exam of score z is added in, does the average score of the exams increase by 50%?

(1) 3x = y
(2) 2z - 3y = xy

St 1

We know nothing about Z

St 2

Holds true for all scenarios for example

x=3 ,y=4

x=5, y=6

B
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