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C=5R/2S

S1 R=4S
4S/2S=2
so 5*2 = 10
Suff

S2
R=2/5
so (5*2/5)/1/2S
(5*2/5)*2S
4S
depending on the value of S, Cs value will change
NS

A
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If C = 5r/(2s) and s ≠ 0, what is the value of C?

(1) r = 4s
(2) r = 2/5

A) C = 5*4s/2s = 10 -------> suff

B) C = 5*2/5 / 2s = 1/s -------> insuff

Ans is A) ------> its too easy, am i getting this wrong?
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We know s= 0 why are we not using it to cancel out the denominator as anything multiplied with 0 is zero ie undefined?
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Nasahtahir
We know s= 0 why are we not using it to cancel out the denominator as anything multiplied with 0 is zero ie undefined?

The stem says that s does NOT equal to 0: s ≠ 0.
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Given C = 5r/(2s) and s ≠ 0,
Option 1: r = 4s, C= 54s/2s = 20/2 = 10, Sufficient
Option 2: r = 2/5, C = 5*2/5*2s = 1/s, Not sufficient.

Option 1 is sufficient to given the value of C, Answer is A.
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