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Bunuel
If m is a three-digit integer, what is the value of m?

(1) The sum of the digits of m is n and n + 1 = 10
(2) m is divisible by 100.

Look at statement 2 alone...
m is divisible by 100..
m can be 100, 200, 300, 400..etc.
alone not sufficient. B and D are out.

statement 1:
sum of digits of m is n. n+1 =10.
n = 9.
we can have 441 or 144.
alone not sufficient. A is out.

A+B
m=900.
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m = ABC
(1) The sum of the digits of m is n and n + 1 = 10
Thus n = A+B+C = 9. ABC can be 333, 720, 900... Not sufficient. Eliminate options A & D.

(2) m is divisible by 100.
Thus ABC can be 100, 200, 300....900. Not sufficient. Eliminate B.

(1) + (2) implies ABC = 900. Sufficient.

Thus, option (C)
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Option C

A)
If Sum of three integer (3 digits of m) is n and n+1 = 10 ie n= 9. So there are many possibilities like 135, 153, etc
B) m is divisible by 100 ie can be 100, 200 ...upto 900. Still not possible to get m

A+B) Only option is 900 So answer is C
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rudra316
Let the number m be abc,

(1) a+b+c = 9

Not sufficient to find values of a, b & c

(2) The number is of the form a00
Not sufficient.

(1) & (2)
a+0+0 = 9
a = 9
Number m is 900

Option C


But id doesn't say that m is a positive integer, couldn't it be -900? IMHO is E
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