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Mo2men
If n and m are positive integers, is m a factor of n?

(1) n = 5(3^k), for any positive integer k
(2) m = 3^(k-1), for any positive integer k

We are given that n and m are positive integers and need to determine whether m is a factor of n, i.e., whether n/m = integer.

Statement One Alone:

n = 5(3^k), for any positive integer k

Since we do not have any information regarding m, statement one alone is not sufficient to answer the question.

Statement Two Alone:

m = 3^(k-1), for any positive integer k

Since we do not have any information regarding n, statement two alone is not sufficient to answer the question.

Statements One and Two Together:

Using statements one and two, we can create the following equation:

n/m = 5(3^k)/3^(k-1)

n/m = 5(3^k)/(3^k)(3^-1)

n/m = 5/(3^-1)

n/m = 5 x 3 = 15

Thus, n/m IS an integer.

Answer: C
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The others have done a far greater job, but for my own sake, I'll try to explain in my own words.

If n and m are positive integers, is m a factor of n?

I notice first, that the question is asking for whether n/m would produce an integer.

(1) n = 5(3^k), for any positive integer k

Gives us no information about m, Not Sufficient

(2) m = 3^(k-1), for any positive integer k

Gives us no information about n Not Sufficient

(1) & (2)

n/m = 5*(3^k)/(3^k-1) = 5 * 3k^(k - (k - 1)) = 5 * 3k is an integer! Sufficient
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Mo2men
If n and m are positive integers, is m a factor of n?

(1) n = 5(3^k), for any positive integer k
(2) m = 3^(k-1), for any positive integer k

bb chetan2u

I got that each statement alone is insufficient

for 1 + 2 ,

When I put k=1 in both ,I got n= 5^3and m=3^0=1 answer Yes m factor of n

Put k=2 , n=5^9 and m = 3^1=3 answer No m is not facor of n

So, I picked E BUT ANSWER IS C ,How ?

n = 5(3^k) means n = 5*3^k, not n = 5^3^k as you assumed.

P.S. There is no need to tag bb in quant or verbal forums. Better to tag quant/verbal experts/tutors or moderators. Thank you!
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