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A*B = Even Integer
A,B = ?
1) we don’t know if A & B are integers so B could be an even integer, or A could be a fraction and B could be an odd integer. Insufficient.

2) B = n(n+1) where n is an integer => B is even. Sufficient.

B is the answer.


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chetan2u
If a*b is an even integer, is b a multiple of 2?

(1) a is not a multiple of 2.
(2) b is product of two consecutive integers.

Self made

We are asked if b is a multiple of 2.

According to statement 1
a is not a multiple of 2. For this to happen a has to be an odd number which could be 1,3,5,7 etc. This is not sufficient.

According to statement 2

b is a productive of two consecutive integers. Product of any two consecutive itegers is always even.
For example: 1*2=2, 2*3=6 and so on. This is statement is alone is sufficent. Hence the answer is B.
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B can be a product of 0 and 1 also. Please someone explain
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Param_91
B can be a product of 0 and 1 also. Please someone explain
Param_91

Zero is even (hence a multiple of 2).

Hence, if b = 0 * 1 = 0

We have a definite answer to the question " is b a multiple of 2 " - Yes

Hope this helps.
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chetan2u
If a*b is an even integer, is b a multiple of 2?

(1) a is not a multiple of 2.
(2) b is product of two consecutive integers.

Self made
It doesn't says a and b are integers so you have to consider a and b both can be fractions as well. That makes question easy.
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