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11 Aug 2017, 03:35
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
50% (01:59) correct
50%
(01:58)
wrong
based on 343
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S is a set of positive integers such that if integer x is a member of S, then both x^2 and x^3 are also in S. If the only member of S that is neither the square nor the cube of another member of S is called the source integer, is 8 in S?
(1) 4 is in S and is not the source integer.
(2) 64 is in S and is not the source integer.
(1) 4 is in S and is not the source integer.
(2) 64 is in S and is not the source integer.
11 Aug 2017, 09:07
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Statement 1: if 4 is there and it's not a source , then it must be square of 2, which is the source in this case. Thus cube of 2 i.e 8 is lap there.
Sufficient.
Statement 2: if 64 is tee and it's not the source, then either it can be 8,64 and 8^3
Or it can be 4,16 and 64.
Not sufficient.
Thus A is the answer.
Sent from my Lenovo TAB S8-50LC using GMAT Club Forum mobile app
Sufficient.
Statement 2: if 64 is tee and it's not the source, then either it can be 8,64 and 8^3
Or it can be 4,16 and 64.
Not sufficient.
Thus A is the answer.
Sent from my Lenovo TAB S8-50LC using GMAT Club Forum mobile app
11 Aug 2017, 09:19
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The answer should be A. If 4 is in S and is not the source integer then 2 has to be in the set. If 2 is in the set then 2^3 has to be in the set.
2nd statement isn't sufficient because if 64 is in the set then either 4 or 8 can be in the set. If 4 is in the set then 8 will not be. Giving both yes and no.
2nd statement isn't sufficient because if 64 is in the set then either 4 or 8 can be in the set. If 4 is in the set then 8 will not be. Giving both yes and no.
