Bunuel wrote:
S is a set of positive integers such that if integer x is a member of S, then both x^2 and x^3 are also in S. If the only member of S that is neither the square nor the cube of another member of S is called the source integer, is 8 in S?
(1) 4 is in S and is not the source integer.
(2) 64 is in S and is not the source integer.
Given : S is a set of positive integers such that if integer x is a member of S, then both x^2 and x^3 are also in S.
DS : is 8 in S?
Statement 1 : 4 is in S and is not the source integer. i.e. 2^2 is there. So, 2^3 i.e. 8 will also be there.
SUFFICIENT
Statement 2: 64 is in S and is not the source integer. i.e. 4^3 is there . 4^2 and 4 will also be there. But we can't say anything about 8.
NOT SUFFICIENT
Answer A
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