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08 Dec 2017, 01:38
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
55% (01:38) correct
45%
(01:29)
wrong
based on 110
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If c > d > b, is d an integer?
(1) c = b + 1
(2) \(d=\frac{c+b}{2}\)
New tricky question
(1) c = b + 1
(2) \(d=\frac{c+b}{2}\)
New tricky question
08 Dec 2017, 02:04
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(1) c=1,5 b=0,5 then d lie in 0,5<d<1,5 and can be 1 or 0,7 so it is unclear whether it is integer or not.
Insufficient
(2) d=(c+b)/2
c= 1,5 b=0,5 d= (1,5+0,5)/2=1 - integer
c=1,8 b=0,8 d= (1,8+0,8)/2=1,3 - NOT an integer
(1) + (2)
c= 1,5 b=0,5 d= (1,5+0,5)/2=1 - integer
c=1,8 b=0,8 d= (1,8+0,8)/2=1,3 - NOT an integer
Answer should be E I guess
Insufficient
(2) d=(c+b)/2
c= 1,5 b=0,5 d= (1,5+0,5)/2=1 - integer
c=1,8 b=0,8 d= (1,8+0,8)/2=1,3 - NOT an integer
(1) + (2)
c= 1,5 b=0,5 d= (1,5+0,5)/2=1 - integer
c=1,8 b=0,8 d= (1,8+0,8)/2=1,3 - NOT an integer
Answer should be E I guess
08 Dec 2017, 10:47
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chetan2u
(1) If b is an integer, then c=b+1 is also an integer, else not. But in any case d might or might not be an integer. So Insufficient.
(2) d = (c+b)/2 This tells us that d is the arithmetic mean of c & b, and thus c, d, b are in Arithmetic Progression (AP). But we cant say whether any or all of them are integers or not. Eg, c, d, b could be 3, 2, 1 respectively or they could be 3.3, 3.2, 3.1 respectively. So Insufficient.
Combining the two statements, c, d, b are in AP and c=b+1. But we could have a case where d is an integer (eg, c/d/b could be 3/2.5/2 respectively) OR we could also have a case where d is NOT an integer (eg, c/d/b could be 3.5/3/2.5 respectively). So d might or might not be an integer still. Insufficient.
Hence E answer
