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C should be the answer IMO, assuming all the candies have same weight.
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C should be the answer IMO, assuming all the candies have same weight.

Hi

Its not necessary for all candles to have the same weight. Whether the weights of candles are same or different, if the combined average weight of the two jars is closer to a particular jar - then that jar has got more candles.

You can refer to the solution by niks18 posted above, which explains this thing algebraically.
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amanvermagmat
NikMan
C should be the answer IMO, assuming all the candies have same weight.

Hi

Its not necessary for all candles to have the same weight. Whether the weights of candles are same or different, if the combined average weight of the two jars is closer to a particular jar - then that jar has got more candles.

You can refer to the solution by niks18 posted above, which explains this thing algebraically.

@amanvermagmat- You are absolutely correct, the combined average will always sway towards the jar with the more candies. I also proved this with general weights acting alegbraically in a manner similar to niks18's.
Also, in retrospect, my statement above appears quite foolish. In case all the candies had the same weight, the average wt for all three bags would be that same wt only, irespective of the nos.
Thank-you very much for pointing this out.
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