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08 Jan 2018, 07:37
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C
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Difficulty:
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(medium)
Question Stats:
75% (01:02) correct
25%
(01:05)
wrong
based on 76
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Which of two different jars, A and B, contain more candies?
(1) The average (arithmetic mean) weight of the candies in jar A is 2.5 grams and the average weight of the candies in jar B is 2.8 grams.
(2) When the two jars are combined in a third jar, C, the average weight is 2.7 grams.
(1) The average (arithmetic mean) weight of the candies in jar A is 2.5 grams and the average weight of the candies in jar B is 2.8 grams.
(2) When the two jars are combined in a third jar, C, the average weight is 2.7 grams.
08 Jan 2018, 10:40
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Bunuel
Statement 1: let jar A contain \(x\) candies and jar B contain \(y\) candies. So total weight of Jar A \(=2.5x\) & that of Jar B\(=2.8y\). But we do not have any relation connecting these two weights, hence \(x\) & \(y\) cannot be calculated. Insufficient
Statement 2: No information to calculate number of candies in Jar A & B. Insufficient
Combining 1 & 2: we have \(2.5x+2.8y=2.7(x+y) => \frac{y}{x}=\frac{2}{1}\). Hence Jar B has more candies. Sufficient
Option C
08 Jan 2018, 11:23
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Bunuel
Based on the first statement, we cannot really say which jar has more candles. Based on second statement alone also, there is nothing to be said.
But when we combine the two statements, we see that the net average (weighted average) is inclined more towards average of jar B than towards average of jar A (combined average weight of 2.7 grams is closer to the average weight of jar B 2.8 grams than that of jar A which is 2.5 grams). Thus there are definitely more candles in jar B than in jar A.
Hence C answer
