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C
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Difficulty:
85%
(hard)
Question Stats:
42% (02:34) correct
58%
(02:34)
wrong
based on 36
sessions
History
Date
Time
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Not Attempted Yet
Given that x& = x^2 + 3, what is the value of integer k if there is a remainder of 3 when k& is divided by 4?
(1) 16 < k& < 37
(2) k is a factor of 24.
Can someone please explain this to me? Why are 19 and 28 the only possibility in statement 1?
(1) 16 < k& < 37
(2) k is a factor of 24.
(A). In statement 1, there are two possible
values for k&: 19 and 28. Only 19 has a
11
The Princeton Review Management, LLC 2002
remainder of 3 when divided by 4,
however, so statement 1 is sufficient. All
even values of k will have a remainder of
3 when divided by 4 (can you explain why
this is so?), so statement 2 does not give
you enough information.
values for k&: 19 and 28. Only 19 has a
11
The Princeton Review Management, LLC 2002
remainder of 3 when divided by 4,
however, so statement 1 is sufficient. All
even values of k will have a remainder of
3 when divided by 4 (can you explain why
this is so?), so statement 2 does not give
you enough information.
Can someone please explain this to me? Why are 19 and 28 the only possibility in statement 1?
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24 Jan 2018, 04:25
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nehalkapadi123
hi K&=K^2+3..
so k^2+3 when divided by 4 leaves a remainder of 3..
so K^2 must be divisible by 4... so k could be any even number
1)16<K&<37
\(16<K^2+3<37\)....
\(K^2+3>16.....K^2>13...\) so K >3 and K is an integer
\(K^2+3<37.....K^2<36..\) .so K<6
possible values of K are 4 and 5
but 5^2 is not div by 4, so our answer 4..
suff
2) K is a factor of 24
nothing much
insuff
A
24 Jan 2018, 04:31
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chetan2u
This would be correct if we were told that k is a positive integer. From (1) k could also be -4. (2) indirectly tells us that k must be positive, so the answer is C. Not a good question overall.
