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Bunuel
If x and y are integers, is x less than y ?

(1) The cube of x is less than the cube of y.

(2) The square of x is less than the square y.

IMO A

Stmt 1: \(x^3\)<\(y^3\)
=> \(x^3\)-\(y^3\)<0
=> (x-y)(\(x^2\)+y^2\(\)+xy)<0; Now, (\(x^2\)+\(y^2\)+xy) will be >0
Thus, x-y<0 => x<y; Sufficient

Stmt 2: \(x^2\)<\(y^2\)
=> (x+y)(x-y)<0; Now either could be <0; Insufficient
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