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Bunuel
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Bunuel
Is p^3 < p?

(1) p < 1

(2) p is an integer

we are looking whetherp^3\(\) is less than p or not.

statement 1: it states that p<1. thus, p could be 0 , -2, - 100, -1/2. If we just consider p=0, p^3\(\) and p will be same. Thus, statement 1 is not sufficient.

statement 2: p is and integer.
o is also an integer. in that case p^3 and p will be same. Integer can be negative or positive. thus answer will vary.

statement 1+2: still not sufficient. statement 1 tells us the range and statement 2 tells us that p is an integer. because of 0, we won't get the perfect answer.

thus , the correct answer is E.
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question becomes -

is P^3 -P <1

or is (p-0)(p-1)(p- (-1)) < 0

drawing number line says this is true only when P is b/n 0 and 1 (not inclusive) and P is <-1 (non inclusive)

1) P < 1 clearly NS ( as the equation is > 0 b/n -1 and 0 and -ve b/n 0 and 1)
2) P is an integer again NS

(1) + (2) -
equation doesn't hold true If P is -1 ( equation is > 0) .
equation holds true for integers to left of -1 i.e. P(p-1)(p+1) is < 0

Answer (E)
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Bunuel
Is p^3 < p?

(1) p < 1

(2) p is an integer


(1) p < 1

Let p = 0................Answer is No

Let p = -2...............Answer is Yes

Insufficient

(2) p is an integer

Let p = 0................Answer is No

Let p = -2...............Answer is Yes

Insufficient

Combine 1 & 2

Same examples lead to no clear cut

Answer: E
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