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24 Apr 2018, 05:47
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
52% (01:57) correct
48%
(01:52)
wrong
based on 152
sessions
History
Date
Time
Result
Not Attempted Yet
If r is greater than 120 percent of s, is r > 70?
(1) 60 < s < 80
(2) r - s = 40
(1) 60 < s < 80
(2) r - s = 40
24 Apr 2018, 06:02
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And: D
Both statement alone sufficient to ans the question..
given r > 120% of s
from 1: minimum value of s is 60 so r must be greater than 120 % of 60 which is = 72 (Sufficient)
from 2: given r-s= 40 means 1.20s-s=40 so .2s=40: so s=200 thus r>70 (sufficient)
Both alone sufficient to ans.
Both statement alone sufficient to ans the question..
given r > 120% of s
from 1: minimum value of s is 60 so r must be greater than 120 % of 60 which is = 72 (Sufficient)
from 2: given r-s= 40 means 1.20s-s=40 so .2s=40: so s=200 thus r>70 (sufficient)
Both alone sufficient to ans.
24 Apr 2018, 12:30
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Given that
\(r > \frac{120}{100} s\) ; \(r > 70 ?\)
Statement 1
\(60 < s < 80\)
For min value of s = 60, \(\frac{120}{100}* 60\) => r > 72
Sufficient
Statement 2
\(r - s = 40\)
=> \(s = r- 40\)
=> \(r > \frac{120}{100}* (r-40)\)
=> \(r > \frac{6}{5} r - 48\)
=> \(r < 48 * 5\)
But we don't know if r > 70, hence Insufficient
IMO A
\(r > \frac{120}{100} s\) ; \(r > 70 ?\)
Statement 1
\(60 < s < 80\)
For min value of s = 60, \(\frac{120}{100}* 60\) => r > 72
Sufficient
Statement 2
\(r - s = 40\)
=> \(s = r- 40\)
=> \(r > \frac{120}{100}* (r-40)\)
=> \(r > \frac{6}{5} r - 48\)
=> \(r < 48 * 5\)
But we don't know if r > 70, hence Insufficient
IMO A
