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adkikani
If x and y are positive integers, is y a prime number?

(1) xy is a prime number.

(2) \(y^2\) is even.

IMO: C

St 1: NOT SUFFICIENT
X Y Is Y Prime
5 1 No
1 5 Yes

St 2: NOT SUFFICIENT
\(y^2\) is even means Y is even
So Y = 2,4 ---- both even and composite

Together: only 1 condition X =1 and Y =2
thus SUFFICIENT

Whats the OA ?

Regards
Anugrah
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You are right, OA = C.

Same has been updated in the question.

anugrahs
adkikani
If x and y are positive integers, is y a prime number?

(1) xy is a prime number.

(2) \(y^2\) is even.

IMO: C

St 1: NOT SUFFICIENT
X Y Is Y Prime
5 1 No
1 5 Yes

St 2: NOT SUFFICIENT
\(y^2\) is even means Y is even
So Y = 2,4 ---- both even and composite

Together: only 1 condition X =1 and Y =2
thus SUFFICIENT

Whats the OA ?

Regards
Anugrah

Posted from my mobile device
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Bunuel gmatbusters niks18 chetan2u VeritasPrepKarishma

Quote:
If x and y are positive integers, is y a prime number?

(1) xy is a prime number.

(2) \(y^2\) is even.

Is there any better approach than plugging numbers for this Q?
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Bunuel gmatbusters niks18 chetan2u VeritasPrepKarishma

Quote:
If x and y are positive integers, is y a prime number?

(1) xy is a prime number.

(2) \(y^2\) is even.

Is there any better approach than plugging numbers for this Q?

hi adkikani

Solve the question logically.

Statement 1: x*y = Prime No, implies either y=Prime or y=1, because x is a positive integer

Statement 2: \(y^2\)=Even implies, y can be any EVEN number

Combining 1 & 2: we know y is even, hence it cannot be 1. So y is Prime
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niks18

Let me know if we are on same page.

Quote:
Solve the question logically.

Statement 1: x*y = Prime No, implies either y=Prime or y=1, because x is a positive integer

You used basic properties of prime numbers here:
1. A prime no is one whose factors are 1 and number itself.
2. 1 is not a prime no.

Eg : 2 * 1 = 2 or 1 * 2 = 2
I get both conditions in question and St 1 satisfied, but am not getting unique answer for y :
I get answer as y is prime in second case and y is not prime in first case. Hence insuff.

Quote:
Statement 2: \(y^2\)=Even implies, y can be any EVEN number

A square of an even integer will be even and likewise for odd. Clearly insuff.
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You got it right,
niks18 has explain it very well.

:thumbup:

adkikani
niks18

Let me know if we are on same page.

Quote:
Solve the question logically.

Statement 1: x*y = Prime No, implies either y=Prime or y=1, because x is a positive integer

You used basic properties of prime numbers here:
1. A prime no is one whose factors are 1 and number itself.
2. 1 is not a prime no.

Eg : 2 * 1 = 2 or 1 * 2 = 2
I get both conditions in question and St 1 satisfied, but am not getting unique answer for y :
I get answer as y is prime in second case and y is not prime in first case. Hence insuff.

Quote:
Statement 2: \(y^2\)=Even implies, y can be any EVEN number

A square of an even integer will be even and likewise for odd. Clearly insuff.
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Thanks for the well-explained answers. But here I would like to point out one thing:

In GMAT, Data Sufficiency questions require the exam takers to decide whether either statement (or both statements) gives data that is sufficient for finding an answer, NOT necessarily a positive answer.

Hence in this case, since the second statement can help us prove the statement wrong, I think it should be recognized as sufficient for finding the answer to the question of whether y is a prime number or not.

In conclusion, I think the answer to this question is B.

Is there any chance that the official answer is wrong?
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Daikon123
Thanks for the well-explained answers. But here I would like to point out one thing:

In GMAT, Data Sufficiency questions require the exam takers to decide whether either statement (or both statements) gives data that is sufficient for finding an answer, NOT necessarily a positive answer.

Hence in this case, since the second statement can help us prove the statement wrong, I think it should be recognized as sufficient for finding the answer to the question of whether y is a prime number or not.

In conclusion, I think the answer to this question is B.

Is there any chance that the official answer is wrong?


Hello! :)

In the primary Question stem, the given info. is that both X & Y are +ve.

We are req. to find out whether "Y" is a prime number.

In Statement 2, it is given that "Y^2 is even".
Thus, we can conclude that "Y" can be any even number.

From the given statements together, we can say that option C would be sufficient to answer the question.

Hope this helps.
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