Statement (1) Integers a, b, c, d, e are evenly spaced from each other such that a < b < c < d < e.
Case 1: a = odd Integer1.a= odd integer and the spacing between number is even = 2.
3 , 5, 7, 9, 11 ----> Product of odd will odd
2. .a= odd integer and the spacing between number is odd = 3.
3, 6, 9, 12, 15 ----> Product of Odd and Even will be even
Case2 :a = even Integer Product will always be even
so first statement is insufficient as we get 2 answer odd and even in different cases
Statement (2) Sum of a, b, c, d, e is odd.
1. all odd ( Spacing between does not matter)3 +7+ 9+ 13+ 15= odd . ----> product of all 5 digits will be odd
2. combination of even odd( Spacing between does not matter)3 +4+ 9+ 14+ 15 = odd ----> product of all 5 digits will be even
so Second statement is also insufficient as we get 2 answer odd and even in different cases
combining two statements.
1. all odd3 +5+ 7+ 9+ 11= odd . ----> product of all 5 digits will be odd
2. combination of even & odd3 +6+ 9+ 12+ 15 = odd ----> product of all 5 digits will be even
if we combine two statements still we get we odd and even so insufficient.
Answer Is E.*******************************************************************************
Kudos
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