Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
Updated on: 14 Sep 2024, 03:07
Originally posted by EgmatQuantExpert on 04 Jul 2018, 06:49.
Last edited by Bunuel on 14 Sep 2024, 03:07, edited 3 times in total.
Last edited by Bunuel on 14 Sep 2024, 03:07, edited 3 times in total.
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
83% (01:21) correct
17%
(01:28)
wrong
based on 313
sessions
History
Date
Time
Result
Not Attempted Yet
The average of 6 numbers is 8. One new number is now added to the set of 6 numbers and the arithmetic mean of the 7 numbers is now calculated.
Is the arithmetic mean of 7 numbers greater than 10?
(1) The additional number is at least 23.
(2) The additional number is a multiple of 4.
Solve any Mean and Standard deviation question under a minute- Exercise Question #2
Options
To solve question 3: Question 3
To read the article: Solve any Mean and Standard deviation question under a minute
Is the arithmetic mean of 7 numbers greater than 10?
(1) The additional number is at least 23.
(2) The additional number is a multiple of 4.
Solve any Mean and Standard deviation question under a minute- Exercise Question #2
Options
- A. Statement (1) ALONE is sufficient, but statement (2) ALONE is not sufficient.B. Statement (2) ALONE is sufficient, but statement (1) ALONE is not sufficient.C. Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.D. EACH statement ALONE is sufficient.E. Statement (1) and (2) TOGETHER are NOT sufficient.
To solve question 3: Question 3
To read the article: Solve any Mean and Standard deviation question under a minute
Updated on: 07 Jul 2018, 07:13
Originally posted by EgmatQuantExpert on 04 Jul 2018, 06:50.
Last edited by EgmatQuantExpert on 07 Jul 2018, 07:13, edited 3 times in total.
Last edited by EgmatQuantExpert on 07 Jul 2018, 07:13, edited 3 times in total.
Kudos
Bookmarks
Solution
Given:
- • The mean of 6 positive integers = 8
• One additional positive integer is now added in the set.
To find:
- • We need to find if the mean of 6 integers is less than 10 or not.
- o 8= \(\frac{Sum\ of\ 6\ integers}{6}\)
o Sum of 6 integers= 48
- •Now, for average of 7 integers to be at least 10, the sum of 7 integers must be 70.
- o Or, new integer must be 22.
o Thus, we need to find if the new integer is ≥ 22 or not.
Statement-1: “The additional integer is at least 23. “
Since new integer is greater than 22, statement 1 alone is sufficient to answer the question.
Statement-2: “The additional integer is multiple of 4 “
The additional integer can be 4 or 8 or 16 or 20 or 24 and so on.
Since new integer can be both, less than 22 and greater than 22, Statement 2 alone is not sufficient to answer the question.
Hence, the correct answer is option A.
Answer: A
04 Jul 2018, 06:55
Kudos
Bookmarks
EgmatQuantExpert
Given Avg. of Six numbers is 8 i.e sum of 6 numbers is 48. Now, the avg of 7 numbers to be greater than 10, their sum must be at least 70.
Option A: new number is at least 23 i.e sum=48+23=71 Sufficient
Option B: new number is multiple of 4, it can be 4,8,12,16,20,24 etc Not sufficient
IMO Option A is correct
