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05 Jul 2018, 23:46
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
67% (01:42) correct
33%
(01:24)
wrong
based on 48
sessions
History
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Not Attempted Yet
If x is 200 units away from 50 on a number line, what is the distance between x and z?
(1) Distance between 50 and z is 100.
(2) \(xz>0\)
New question
(1) Distance between 50 and z is 100.
(2) \(xz>0\)
New question
chetan2u
There are 2 cases when x is 200 units away from 50 on a number line.
Number line:-(-150)---------0---------(Reference=50)-----------------(x=250)----
Statement-1:-
Distance between 50 and z is 100.
Number line:-(x=-150)----(z=-50)-----0---------(Reference=50)-------(z=150)----------(x=250)----
Now,distance between x and z:-
1.|x-z|=|-150-(-50)|=|-150+50|=|-100|=100 unit
2.|x-z|=|250-150|=|100|=100 unit
3.|x-z|=|-150-150|=|-300|=300 unit
4.|x-z|=|250-(-50)|=|300|=300 unit
So, insufficient
Statement-2:-
\(xz>0\)
x has two positions but there is no info available on z.
So, insufficient.
combining, we have both x and z same polar sign so that xz>0
1.|x-z|=|-150-(-50)|=|-150+50|=|-100|=100 unit
2.|x-z|=|250-150|=|100|=100 unit
So, sufficient.
Ans. (C)
06 Jul 2018, 00:18
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chetan2u
Given x is 200 units away from 50 on the number line, x can be on the right or left of 50, we do not know,
hence x = 250 or x = -150 on the number line
.......(-150)................................0.................(50)....................................(250)
we need to find distance between x & z or l x - z l
Statement 1: Distance between 50 and z is 100.
Hence , we have
.......(-150).............(-50)...................0.................(50).......................(150).............(250)
z = -50 or z = 150
we get l x - z l = 300 or 100
Statement 1 alone is Not Sufficient.
Statement 2: x*z > 0
Hence x & z have the same sign, either both are positive or both are negative.
However we do not know value of z. Hence Statement 2 is Not Sufficient.
Combining 1 & 2, we get
if x & z both are positive, then x & z both lie on the right of 50
0.................(50).......................(150).............(250)
x = 250 & z = 150
hence l x - z l = 100
if x & z both are negative, then x & z both lie on the left of 0
.......(-150).............(-50)...................0.................(50)
x = -150 & z = -50
hence l x - z l = 100
Both cases give the same value for l x - z l
We get that Combining the 2 statements is Sufficient.
Answer C.
Thanks,
GyM
