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18 Jul 2018, 23:17
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
44% (01:51) correct
56%
(01:43)
wrong
based on 139
sessions
History
Date
Time
Result
Not Attempted Yet
If ab ≠ 0, what is the value of \(\frac{a+b}{a-b}\) ?
(1) \(3a^2 = 2b^2\)
(2) b = 10
(1) \(3a^2 = 2b^2\)
(2) b = 10
18 Jul 2018, 23:43
Kudos
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Statement 1: This provides only the ratio a/b. Hence insufficient
Statement 2: b=10. Provides no info about a. Insufficient
Statement 1&2: We can solve statement 1 and get values of a and b. Sufficient
Posted from my mobile device
Statement 2: b=10. Provides no info about a. Insufficient
Statement 1&2: We can solve statement 1 and get values of a and b. Sufficient
Posted from my mobile device
To find the value of \(\frac{a+b}{a-b}\)
Statement 1
\(3a^2 = 2b^2\)
=> \(\frac{a^2}{b^2}\) = \(\frac{2}{3}\)
=> \(\frac{a}{b}\) = \(\pm \sqrt{\frac{2}{3}}\)
Statement 1 is not sufficient
Statement 2
b = 10
Does not give any information about value of a
Statement 2 is insufficient
Combining statements 1 and 2
=> \(3a^2 = 200\)
=> a = \(\pm \sqrt{\frac{200}{3}}\)
We don't get the unique value for "a"
Statements 1 and 2 together are not sufficient
Hence option E
Statement 1
\(3a^2 = 2b^2\)
=> \(\frac{a^2}{b^2}\) = \(\frac{2}{3}\)
=> \(\frac{a}{b}\) = \(\pm \sqrt{\frac{2}{3}}\)
Statement 1 is not sufficient
Statement 2
b = 10
Does not give any information about value of a
Statement 2 is insufficient
Combining statements 1 and 2
=> \(3a^2 = 200\)
=> a = \(\pm \sqrt{\frac{200}{3}}\)
We don't get the unique value for "a"
Statements 1 and 2 together are not sufficient
Hence option E
