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A positive integer N is a six digit number of the form xyxyyy where x and y are distinct digits. What is the value of x?

(1) N is divisible by 6.
just tells us that x+y+x+y+y+y+y is divisible by 3 and y is even
so 2(x+2y) is div by 3
x can be 3 and y = 0
x can be 5, and y = 2
insuff

(2) N is divisible by each integer from 1 to 5.
this means y is multiple of 5, hence 0 or 5
x can be anything
insuff

combined
y=0, x can be 3 and nunmber 303000
also y=0, x=6 0r 9
insuff

e




Hello, I have a question about statement 2.

(2) N is divisible by each integer from 1 to 5.


Doesn't this means that N is divisible by 1,2,3,4 and 5? If so, doesn't this statement mean that N is divisible by 2 and 3 as well as 5 and makes y=0 and x=3 making option C sufficient? Thanks.
chetan2u

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Hi..
Number is xyxyyy .
Div by 1 to 5 means div by LCM of 1,2,3,4,5, =60 so Ans can be 303000 or 606000 or 909000
So X could be 3, or 6, or 9
Insuff
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Thanks @chetan2u...understood.

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chetan2u
A positive integer N is a six digit number of the form xyxyyy where x and y are distinct digits. What is the value of x?

(1) N is divisible by 6.
just tells us that x+y+x+y+y+y+y is divisible by 3 and y is even
so 2(x+2y) is div by 3
x can be 3 and y = 0
x can be 5, and y = 2
insuff

(2) N is divisible by each integer from 1 to 5.
this means y is multiple of 5, hence 0 or 5
x can be anything
insuff

combined
y=0, x can be 3 and nunmber 303000
also y=0, x=6 0r 9
insuff

e


Hi,
for the reason of {2}, i guess , i am missing something please correct me if needed.

N is divisible by each integer from 1 to 5.
this means y is multiple of 5, hence 0 or 5

1,2,3,4,5 are all factors of the number xyxyyy

for 5 divisibility the last digit need to be 0 or 5. But for 4 divisibility it need to be last two digits must be divisible by 4 so cannot be ( 55 ), but 00 (yes).
for 3 divisibility sum should be multiple of 3k ie x can be 3,6,9
x= 3,6,9 y=0.

right.
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Tamao411284
chetan2u
A positive integer N is a six digit number of the form xyxyyy where x and y are distinct digits. What is the value of x?

(1) N is divisible by 6.
just tells us that x+y+x+y+y+y+y is divisible by 3 and y is even
so 2(x+2y) is div by 3
x can be 3 and y = 0
x can be 5, and y = 2
insuff

(2) N is divisible by each integer from 1 to 5.
this means y is multiple of 5, hence 0 or 5
x can be anything
insuff

combined
y=0, x can be 3 and nunmber 303000
also y=0, x=6 0r 9
insuff

e


Hi,
for the reason of {2}, i guess , i am missing something please correct me if needed.

N is divisible by each integer from 1 to 5.
this means y is multiple of 5, hence 0 or 5

1,2,3,4,5 are all factors of the number xyxyyy

for 5 divisibility the last digit need to be 0 or 5. But for 4 divisibility it need to be last two digits must be divisible by 4 so cannot be ( 55 ), but 00 (yes).
for 3 divisibility sum should be multiple of 3k ie x can be 3,6,9
x= 3,6,9 y=0.

right.

Hello

I think your analysis is correct. Since from second statement we get y=0 but there is no unique value of x, hence second statement is not sufficient.
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