Bunuel
If x and y are positive integers and 18 is a multiple of x*y^2, what is the value of y?
(1) x is a factor of 54 and is less than half of 54.
(2) y is a multiple of 3
Solution
Step 1: Analyse Question Stem
• x and y are positive integers.
o So, \(y^2\) must be a perfect square.
• 18 is a multiple of \(x*y^2\)
o \(18 = k*x*y^2\) where k is a positive integer.
• Now, positive factors of 18 = 1, 2, 3, 6, 9 and 18
o Perfect squares which are factors of 18 = 1 and 9
So, \(y^2\) can be either 1 or 9
Or, y can be either 1 or 3
• We need to find the value of y and we can figure out the value of y in either of the following two ways:
o if we can directly find out whether y is 1 or 3.
o Or, if we can determine \(k*x\)
Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: x is a factor of 54 and is less than half of 54.• x is a factor of 54 and x < 54/2 or x < 27
o So, there are more than one values possible for x. For example:
x can be 1, in that case k could be 2 and hence \(y = 3\)
x can also be 2, in that case k could be 9 and hence \(y = 1\)
Also, x can be 9, in that case k could be 2 and hence \(y = 1\)
Since multiple possibilities exists for the value of \(k*x\) where y can either be 1 or 3, so we won't be able to determine the exact value of y from this statement.
Hence, statement 1 is not sufficient and we can eliminate answer options A and D
Statement 2: y is a multiple of 3• Out of 1 and 3 only 3 is a multiple of 3.
Thus, the correct answer is
Option B.