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30 Oct 2019, 21:33
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35%
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Question Stats:
70% (01:46) correct
30%
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based on 142
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The average of 5 different numbers is 14. What is the average (arithmetic mean) of the 3 largest numbers?
(1) The average (arithmetic mean) of the two smallest numbers is 5.
(2) The average (arithmetic mean) of the two smallest numbers is 1/4 of the average of the 3 largest numbers.
(1) The average (arithmetic mean) of the two smallest numbers is 5.
(2) The average (arithmetic mean) of the two smallest numbers is 1/4 of the average of the 3 largest numbers.
Archit3110
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31 Oct 2019, 00:33
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Bunuel
given
a+b+c+d+e=70
find c+d+e/3
#1 The average (arithmetic mean) of the two smallest numbers is 5
10+c+d+e=70
c+d+e = 60
avg = 20 sufficeint
#2
The average (arithmetic mean) of the two smallest numbers is 1/4 of the average of the 3 largest numbers.[/quote]
a+b/2 = 1/4 * ( c+d+e)/3
6(a+b) = c+d+e
a+b=10
so c+d+e= 60
sufficient
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01 Aug 2020, 10:29
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For statement 2, how did you figure out that a+b=10?
