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anmolmakkarz17
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chetan2u
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ManjariMishra
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Hi! Can someone explain this problem?
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adstudy
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anmolmakkarz17
If 0 < x < 1 and m=(\(\frac{1}{2^n}\)) , where n is a positive integer, what is the thousandths digit of \(\frac{x}{m}\)?

1) The thousandths digit of x is greater than 0.
2) 1,000x is a multiple of 5.

x is of the form 0.abc...

and m is of the form \(\frac{1}{2^n}\) where n = 1,2,3,....

we need \(\frac{x}{m}\) which is equal to \(0.abc...* 2^n\)

Hence we need the value of \(c*2^n\)

From Statement 1 - The thousandths digit of x is greater than 0.

Not much info we get from this statement. This means that c is not equal to zero, except zero it can anything from 1 to 9.

Not Sufficient

From Statement 2 - 1,000x is a multiple of 5

This means that the new number after multiplying with 1000 becomes 'ab5.000'

That is we now know the value of c and after decimal no value will exist at it will not be a multiple then. Only integers are multiple of integers.

hence we now know that x would be something like this -> '0.ab5'.

When multiplied by any positive integer power of 2 will give us 0 in the thousandth place.

Hence Sufficient.

Hence answer B
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Hi chetan2u

Isn't this question wrong? Since option A is giving wrong info, it's not data sufficiency anymore.
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