For integers m, how many positive perfect cubes would be less than m?

Question

(1) 4 < m^2 < 9900

(2) 31 < m < 65

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chetan2u · Answer

For integers m, how many positive perfect cubes would be less than m?

(1) 4 < m^2 < 400
So 2<m<20.....
If m is 8, then only 1
If m is 9, then 1 and 8, so 2
Insufficient

(2) 31 < m < 65
Now there is only one perfect cube 64, and m is at the max 64, so the positive perfect cubes less than m will always be the SAME as positive perfect cube less than 31.
So irrespective of value of m , the answer is 1, 9, 27— 3 integers 
Sufficient

B

Archit3110 · Answer

#1
4 < m^2 < 400
2<m<20
m= 8 we get only 1 cube i.e 2
if m = 9 then we have cube ; 8,27,64
insufficient
#2
31<m<65
only 64 possible
IMO B

shameekv1989 · Answer

Bunuel

For integers m, how many positive perfect cubes would be less than m?

(1) 4 < m^2 < 990

(2) 31 < m < 65

Aren't the statements still contradicting each other? Since it is given that m is an integer m^2 can not be any value from 961 - 990 (It can be either 961 or 1024)

i) 2 < m < 32 - max value of m can be 31

ii) 31 < m < 65 - min value of m can be 32

There is no overlap of integer m in the 2 statements.

Bunuel · Answer

____________________
Edited option 1.

borjaapaolaza · Answer

Dear  Bunuel  ,

Aren't -1, -8, -27... perfect cubes to?

For integers m, how many positive perfect cubes would be less than m?

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GMAT Data Sufficiency (DS) Questions

For integers m, how many positive perfect cubes would be less than m?

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