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Bunuel
Given the equation x^2 + bx + c = 0, where b and c are constants, what is the value of c?

(1) The sum of the roots of the equation is zero.

(2) The sum of the squares of the roots of the equation is equal to 18.


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Visit https://www.mathrevolution.com/gmat/lesson for details.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

Assume \(p\) and \(q\) are roots of the equation of \(x^2+bx+c = 0\).
Then we have \((x-p)(x-q) = x^2+bx+c = 0\).
We have \(x^2 - (p+q)x + pq = x^2 + bx + c\).
Thus we have \(p+q = -b\) and \(pq = c\).

Since we have 4 variables (\(p\) and \(q\)) and 2 equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
We have \(p+q = -b = 0\) from condition 1).
We have \(p^2 + q^2 = (p+q)^2 - 2pq = 0 - 2c = -2c = 18\).
Thus we have \(c = -9\).

Since both conditions together yield a unique solution, they are sufficient.

Therefore, C is the answer.

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.­
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For a standard quadratic equation of the form a\(x^2\) +bx+c = 0,
Sum of roots = -(b/a) and Product of roots = c/a.

Comparing the equation \(x^2\)+bx+c = 0 to the standard form, a =1, b = b and c=c.
Let the roots of the given equation be α and β. Then, α+β = -b and αβ = c.

From statement I alone, we can say that b = 0. This is insufficient to find out the value of c.
Answer options A and D can be eliminated. Possible answer options are B, C or E.

From statement II alone, \(α^2\) + \(β^2\) = 18. This is insufficient to find unique values of α and β, hence insufficient to find a value for c since c = αβ.
Statement II alone is insufficient. Answer option B can be eliminated. The possible answer options are C or E.

Combining both statements together, we have the following:
From statement I alone, we know that α+β = -b = 0.
From statement II alone, we know that \(α^2\) + \(β^2\) = 18
From the question data, we know that αβ = c.

In any question on Algebra, if you have the data about the sum and product of two variables along with the sum of their squares, clearly, the question wants you to apply the Algebraic identity of \((a+b)^2\).

\((a+b)^2\) = \(a^2\) + \(b^2\) + 2ab.

Applying this to our situation, we have \((α+β)^2\) = \(α^2\)+\(β^2\)+2αβ. Substituting the values, we have,

\((0)^2\) = 18 + 2c. Solving this gives us c=-9.
The combination of statements is sufficient. Answer option E can be eliminated.

The correct answer option is C.

Hope that helps!
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