List A: {20, 4, 8, x}
List B: {8, 3, 6, 12, -4}
List A above has 4 numbers and List B above has 5 numbers. What is the value of x?For convenience re-write the lists in ascending order.
List A: {x, 4, 8, 20} (here we don't know the value of x, so let's just write it in the beginning, which might not be the case)
List B: {-4, 3, 6, 8, 12}
(1) The range of the numbers in List A is equal to the range of the numbers in List B.
The range of B is Largest - Smallest = 12 - (-4) = 16.
If the range of A is also 16, it means that x can be any number from 4 to 20, inclusive: \(4 \leq x \leq 20\) (if x is outside this range the range of A would be more than 16. For example, the range of {3, 4, 8, 20} is 17).
Not sufficient.
(2) The median of the numbers in List A is equal to the median of the numbers in List B.[/quote]
The median of B is the middle number, so 6 (the median of a list with even number of elements is the middle element, when arranged in ascending/descending order).
The median of A to also be 6, x must be any number less than or equal to 4: \(x\leq 4\) (if x > 4, then the median of A will be more than 6. For example, the median of {4, 5, 8, 20} is (5 + 8)/2 = 6.5).
(1)+(2) \(4 \leq x \leq 20\) and \(x\leq 4\) has only one value in common, namely 4. So, x = 4. Sufficient.
Answer: C.