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IMO D

Line drawn to tangent subtends 90°
OB^2=BC^2+OC^2 --------(1)

Statement 1: product of line OB*AB=170. (AB = 10)
OB= 170/10 => OB=17 -----(2)
OB=OA+AB => 17-10=0A => OA=7=OC
Putting values in equality (1)
17^2-7^2 = BC^2
289-49 = BC^2
240 = BC^2
BC^2 = 2*2*2*2*3*5
BC = 4√15
{sufficient}

Statement 2: circumference of Circle = 14π = 2πr => r=7
OC=7 , OB=OA+AB = 7+10 = 17
Putting values in equality (1)
17^2-7^2 = BC^2
289-49 = BC^2
240 = BC^2
BC^2 = 2*2*2*2*3*5
BC = 4√15
{sufficient}

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To solve the length of tangent BC, we need only radius.

Statement 1 => AB*OB = 170
AB is 10, so OB = 17 so we have radius
SUFFICIENT

Statement 2 => Circumference is known,
Radius is known
SUFFICIENT

D
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In the given figure, O is the center of the circle and BC is the tangent. If AB = 10cm. What is the length of the tangent BC?

What do we have:
    As a tangent is perpendicular to the circle, we know that OCB is rectangle in C.
    And if we applied the theorem for rectangular triangles, we know that OB^2=OC^2+BC^2 or BC^2 = OB^2 - OC^2
    OB=OA+AB and we already have AB=10cm

So what we are really looking for is the Radius of the circle, OC or OA (all 3 are equal)?


Let's start with (1) The product of the length of OB and AB is 170.
We know: OB=OA+AB and AB=10cm
OB*AB =170 = OB * 10 so OB = 17cm
OB=OA+AB or 17= OA + 10 so OA = 7cm = OC
We have everything, BC^2 = OB^2 - OC^2 = 17^2 + 7^2, no need to do the maths, only the positive value of BC is valid (lengths are positive), so (1) is sufficient and the answer is either A or D.


Let's take (2) The circumference of the circle is 14π.
Circumference of a circle is 2*pi*Radius
We have: 2*pi*R=14*pi so R=7cm = OC = OA
OB=OA+AB = 7+10=17cm
We have everything: BC^2 = OB^2 - OC^2 = 17^2 + 7^2, no need to do the maths, (2) is sufficient. So D

The correct answer is D
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D.
Here angle ocb is 90

1.OB*AB=170
OB=OA+AB
So OA=10=OC=radius
So as per Pythagoras theorem
Oc^2+ob^2 =bc^2

Sufficient

2.2pi radius=14 pi
R=oc=oa

Sufficient

D.

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Angle OCB is 90 degrees. If we can find the radius of the circle we can find the length of BC.

Statement1 - we can find OA - Sufficient.
Statement2 - we can find the radius - Sufficient.

Answer - D

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Option A

as tangent is 90 to the radius so using Pytho theorem we can find the length of tangent
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D ,IMO

In the given figure, O is the center of the circle and BC is the tangent. If AB = 10cm. What is the length of the tangent BC?

In the triangle OBC , angle OCB is 90 (since BC is tangent ). Now to find the length of BC , we just need OB and OC.
To get length of OB and OC , we need the radius of the circle.

Basically the ques now reduced to , what is the length of the radius of the circle ?

(1) The product of the length of OB and AB is 170.
OB . AB = 170 => OB = 17 => OA = 7 = radius .. Sufficient

(2) The circumference of the circle is 14π.

circumference goven . We can easily find radius . Sufficient

Hence D .
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D. Both the statement are sufficient.

AB =10; BC= ?

OCB forms a right angled triangle.

Statement 1: OB*AB= 170

OB= 17
OB-AB= OA= 7
OA=OC 7 (Both are radius)
we know OC and OB
We can find BC using Pythagorean theorem.
Sufficient

Statement 2: The circumference of the circle is 14π.
say d is diameter and r is radius

dπ = 14π ; d = 14 ; r = 7

OC=OA = 7
OA+AB= OB = 17

We know OC and OB
we can find BC using pythagorean therom.
Sufficient
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